Answer:
Step-by-step explanation:
- 4 > - 3, correct as 4 is to the right of - 3
- - 3 > 4, incorrect as - 3 is to the left of 4
- - 2 < - 3, incorrect as - 3 is to the left of - 2
- - 3 < - 6, incorrect as - 6 is to the left of - 3
The place value pattern is a system of patterns of tens in which every
place value is ten times the value on its right. The place value pattern
system is used to <span>write
numbers that are 10 times as much as or 1/10 of any given number.
The place values in the pattern are: ones, tens (10*ones), hundreds (10*tens), thousands (10*hundreds),...
So, 50 = 5 tens
5000= 5 thousands, 0 hundreds, 0 tens, 0 ones
So, 5000 > 50</span>
The formula to solve for this would be pi(r^2)xheight. Essentially what this formula does is it takes the are of the base (pi x r^2) and multiplies it by the height of the cylinder to find how many times the base can stack on itself until it reaches the top. This formula of base are times height works for all prisms with two bases. Here are the steps to solve:
1) plug in the values
- pi(15^2) x 45
2) solve for the base area of one of the circles
- pi(15^2)=225pi
3) multiply the base area by the height
- 225pi x 45 = 10,125pi
4) final answer: the tank can hold 10,125pi cubic feet of water
Answer:
v_top = 2400 mi/hr
v_w = 400 mi/h
Step-by-step explanation:
Given:
- Total distance D = 4800 mi
- Headwind journey time taken t_up= 3 hr
- Tailwind journey time taken t_down = 2 hr
Find:
Find the top speed of Luke's snow speeder and the speed of the wind.
Solution:
- The speed of Luke v_l is in stationary frame is given by:
v_l = v_w + v_l/w
Where,
v_w: Wind speed
v_l/w: Luke speed relative to wind.
- The top speed is attained on his returned journey with tail wind. We will use distance time relationship to calculate as follows:
v_top = D / t_down
v_top = 4800 / 2
v_top = v_down = 2400 mi/hr
- Similarly his speed on his journey up with head wind was v_up:
v_up = D / t_up
v_up = 4800 / 3
v_up = 1600 mi/hr
- Now use the frame relations to find the wind speed v_w:
v_down = v_w + v_l/w
v_up = -v_w + v_l/w
- Solve equations simultaneously:
2400 = v_w + v_l/w
1600 = -v_w + v_l/w
4000 = 2*v_l/w
v_l/w = 2000 mi/h
v_w = 400 mi/h
<span>Two lines are parallel if their slope is the same.
You want to write 8x + 4y = 5 in the form y = mx + b, where m represents the slope and b is the y-intercept.
We need to isolate y in the given equation. The number next to x is the slope.
8x + 4y = 5
4y = -8x + 5
y = (-8x +5)/4
y = -2x + 5/4
The slope of the line we want is -2.
Two lines are perpendicular if the slope of the first line times the
slope of the second line produces a product of negative one.
Since our slope is -2, we know that -2 times 1/2 yields -1.
The slope of the line perpendicular is 1/2.
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