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3 years ago

What is an equation of the the line that passes through the point (3,6)and is parallel to the line 4x-3y=21

Mathematics

1 answer:

disa [49]3 years ago

7 0

Answer:

y=4x/3+9/3

Step-by-step explanation:

slop is 4x/3

and the point is 3,6

so y-6 = 4x/3(x-3)

sove the you will have y=4x/3+9/3

You might be interested in

Y=74(1.01)^8 is it increasing or decreasing

Dvinal [7]

Answer:

Increasing

Step-by-step explanation:

The computation is given below:

Given that

y = 74 × (1.01)^8

= 74 × 1.082856706

= 80.1314

As it can be seen that the initial amount is 74 but after solving the given equation the value is increased as it shows 80.1314

Therefore it is increasing

5 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

rosijanka [135]

y - 0 = 5(x-4)

y = 5x-20

5x - y = 20 Standard Form

3 0

3 years ago

Stardust the unicorn, covered a distance of 50 miles on his first trip to the forest. On a later trip he travelled 300 miles whi

jok3333 [9.3K]

His new time compared with the old time was increased by factor of 2

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration (m / s²)v = final velocity (m / s)</em>

<em>u = initial velocity (m / s)</em>

<em>t = time taken (s)</em>

<em>d = distance (m)</em>

Let us now tackle the problem!

This problem is about Kinematics.

In this problem we assume that the unicorn is moving at a constant speed so that the acceleration is zero.

<u>Given:</u>

first distance = d₁ = 50 miles

second distance = d₂ = 300 miles

v₂ = 3 v₁

<u>Unknown:</u>

t₂ : t₁ = ?

<u>Solution:</u>

To find his new time , we will use the following formula.

$v_2 = 3 v_1$

$\frac{d_2}{t_2} = 3 \times \frac{d_1}{t_1}$

$\frac{300}{t_2} = 3 \times \frac{50}{t_1}$

$\frac{300}{t_2} = \frac{150}{t_1}$

$t_2 = \frac{300}{150} \times t_1$

$\large {\boxed {t_2 = 2 \times t_1} }$

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437

Kinetic Energy : brainly.com/question/692781

Acceleration : brainly.com/question/2283922

The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Sperm , Whale , Travel

8 0

3 years ago

Pls help me out in finding the right answers

Mila [183]

The answers are 1, 2, 5, and 7

8 0

3 years ago

A highway map of Ohio has a coordinate grid superimposed on top of the state. Springfield is at point (1, –4) and Columbus is at

Vedmedyk [2.9K]

The midpoint, where the rest area is, will just be the average of the coordinates of Springfield and Columbus.

Rest Area=((1+7)/2, (-4+1)/2)

Rest Area=(4, -1.5)

The distance between the two cities can be found using the Pythagorean Theorem, which used in the manner is often referred to as the "distance" formula between two points.

d^2=(x2-x1)^2+(y2-y1)

d^2=(7-1)^2+(1--4)^2

d^2=36+25

d^2=61

d=√61 and we are told that each unit is equal to 5.38mi so the distance from Springfield to Columbus is:

D=5.38√61 mi

D≈42.02mi (to nearest hundredth of a mile)

3 0

3 years ago