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irina [24]
3 years ago
13

What is an equation of the the line that passes through the point (3,6)and is parallel to the line 4x-3y=21

Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer:

y=4x/3+9/3

Step-by-step explanation:

slop is 4x/3

and the point is 3,6

so y-6 = 4x/3(x-3)

sove the you will have y=4x/3+9/3

You might be interested in
For the graph of any inequality, which points along the ray are solutions to the inequality?
Juliette [100K]

Answer:

The part where the two rays meet is you solution

Step-by-step explanation:when graphing your solution, you are going to have two rays that will cross if there is one solution, that will be the solution. if they never meet, there is no solution to your problem, but if they are on top of each other, there are infinite solutions.

3 0
3 years ago
Suppose we choose7 objects without replacement from 9 objects
stiks02 [169]

Answer:

<h2>181 440</h2>

Step-by-step explanation:

We have 9 choices for Choosing the first object

              8 choices for Choosing the 2nd object

              .

              .

              .

             3 choices for Choosing the seventh object

Therefore if we want to choose7 objects without replacement from 9 objects we have : 9×8×7×6×5×4×3 = 181 440

Also ,we can calculate it this way :

9P7 = 181 440

7 0
2 years ago
38. Evaluate f (3x +4y)dx + (2x --3y)dy where C, a circle of radius two with center at the origin of the xy
lina2011 [118]

It looks like the integral is

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy

where <em>C</em> is the circle of radius 2 centered at the origin.

You can compute the line integral directly by parameterizing <em>C</em>. Let <em>x</em> = 2 cos(<em>t</em> ) and <em>y</em> = 2 sin(<em>t</em> ), with 0 ≤ <em>t</em> ≤ 2<em>π</em>. Then

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \int_0^{2\pi} \left((3x(t)+4y(t))\dfrac{\mathrm dx}{\mathrm dt} + (2x(t)-3y(t))\frac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^{2\pi} \big((6\cos(t)+8\sin(t))(-2\sin(t)) + (4\cos(t)-6\sin(t))(2\cos(t))\big)\,\mathrm dt \\\\ = \int_0^{2\pi} (12\cos^2(t)-12\sin^2(t)-24\cos(t)\sin(t)-4)\,\mathrm dt \\\\ = 4 \int_0^{2\pi} (3\cos(2t)-3\sin(2t)-1)\,\mathrm dt = \boxed{-8\pi}

Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on <em>C</em> nor in the region bounded by <em>C</em>, so

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \iint_D\frac{\partial(2x-3y)}{\partial x}-\frac{\partial(3x+4y)}{\partial y}\,\mathrm dx\,\mathrm dy = -2\iint_D\mathrm dx\,\mathrm dy

where <em>D</em> is the interior of <em>C</em>, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: -2\times \pi\times2^2 = -8\pi.

3 0
3 years ago
The area is 24 what are the possible dimensions l×w
taurus [48]
Hey there I see you need help well that's why I am here for a square the one side could be 6 or for a rectangle the l vould be 6 and the W could be 4 or 8 and 3 or lastly 12 and 2 hope this helps
5 0
3 years ago
Read 2 more answers
Given the diagram shown below which of the following best represents the distance from the school to the library?
Amanda [17]
To answer this question, we will use the sine law which is illustrated in the attached image.

We are given that:
The distance from school to library = a
∠A = 32
∠B = 110
b = 2.2

Substitute with the givens in the relation of the sine law to get a as follows:
(sin 32) / (a) = (sin 110) / (2.2)
a = (2.2 sin 32) / (sin 110)
distance from school to library = a = 1.2406 mi

Based on the above calculations, the best choice would be:
B. 1.2 mi

4 0
3 years ago
Read 2 more answers
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