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irina [24]
3 years ago
13

What is an equation of the the line that passes through the point (3,6)and is parallel to the line 4x-3y=21

Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer:

y=4x/3+9/3

Step-by-step explanation:

slop is 4x/3

and the point is 3,6

so y-6 = 4x/3(x-3)

sove the you will have y=4x/3+9/3

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What is the slope of the line that passes through the points (3,-2) and (9,-2)?
djyliett [7]

Answer:

0

Step-by-step explanation:

slope= (y2-y1)/(x2-x1)

= [-2-(-2)]/[9-3]

=[-2+2]/6

=0/6

=0

Hope it helps:)

7 0
3 years ago
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Arthur took out a $12,000 personal loan. The monthly payments 0/
Brrunno [24]

Answer:

Answer C, Arthur will pay about $918 less in interest if he chooses the 3-year loan.

Step-by-step explanation:

(370.53 x 12) x 3 = 13,339.08

(237.61 x 12) x 5 = 14,256.60

14,256.60 - 13,339.08 = 917.58 (then round up)

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3 years ago
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B, there are two sections that say 1, and there are less sections then the other one with two ones
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3 years ago
Complete the congruence statement for the figure shown. If the triangles cannot be shown congruent, type na in each blank.
Serjik [45]

Answer:

ΔABC≅ΔDEF by AAS (Angle-Angle-Side) Theorem

Step-by-step explanation:

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7 0
3 years ago
A fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. They want to construct a 99% c
Lana71 [14]

Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when M = 0.06, \sigma = 1.1

0.06 = 2.575*\frac{1.1}{\sqrt{n}}

0.06\sqrt{n} = 2.575*1.1

\sqrt{n} = \frac{2.575*1.1}{0.06}

(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}

n = 2228.6

Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

7 0
3 years ago
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