One example is when n is 11. 11^2 + 4 = 125. 11 is odd but the 11th term of the sequence, 125, is not prime because 125 is divisible by 5 and 25.
Trying to factor by splitting the middle term
Factoring <span> b2-4b+4</span>
The first term is, <span> <span>b2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -4b </span> its coefficient is <span> -4 </span>.
The last term, "the constant", is <span> +4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> 1 • 4 = 4</span>
Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is <span> -4 </span>.
<span><span> </span></span>
<span><span>-4 + -1 = -5</span><span> -2 + -2 = -4 That's it</span></span>
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -2
<span>b2 - 2b</span> - 2b - 4
Step-4 : Add up the first 2 terms, pulling out like factors :
b • (b-2)
Add up the last 2 terms, pulling out common factors :
2 • (b-2)
Step-5 : Add up the four terms of step 4 :
(b-2) • (b-2)
Which is the desired factorization
49 is the answer to ur question
Answer:
y = 2
Step-by-step explanation:
Given
![\sqrt[3]{3y+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3y%2B2%7D)
+ 4 = 6 ( subtract 4 from both sides )
= 2 ( cube both sides )
3y + 2 = 2³ = 8 ( subtract 2 from both sides )
3y = 6 ( divide both sides by 3 )
y = 2
Answer:
f(-2) = 0
f(0) = -4
f(4) = 12
Step-by-step explanation:
Given the function f(x) = x^2 - 4, we must plug in the values substituting x for each of the answers.
f(-2) = (-2)^2 - 4
-2 times itself is a positive 4, therefore:
f(-2) = 4 - 4
f(-2) = 0
We do the same for each answer.
f(0) = (0)^2 - 4
f(0) = -4
f(4) = (4)^2 - 4
f(4) = 16 - 4
f(4) = 12
