I dont see any choices sorry wish i could help
<h2>b) is the correct option </h2>
Explanation:
The biological species concept defines a species as a group of individuals living in one or more populations that can potentially interbreed to produce healthy, fertile offspring
- The biological species concept connects the idea of a species to the process of evolution
- Because members of a species can interbreed, the species as a whole has a common gene pool, a collection of gene variants
- In order to be considered to be a single species in the biological species concept, a group of organisms must produce healthy, fertile offspring when they interbreed
- In some other cases, organisms of different species can mate and produce healthy offspring, but the offspring are infertile, can’t reproduce
Hence it includes the groups which are reproductively isolated so asexual fungi will be least relevant to this group
Answer:
Ss and ss
Explanation:
<em>Since the smooth trait (S) is dominant over the wrinkle trait (s), the genotype of the wrinkled pea parent is definitely </em><em>ss</em><em>.</em>
<em>Also, some of the progeny had wrinkled pea texture (ss). Each of the 2 wrinkled alleles must have been donated by each of the parent. It thus means that the smooth pea parent is heterozygous for the trait (</em><em>Ss</em><em>).</em>
Now, let us look at a cross between the two parents;
Ss x ss
Progeny: Ss, Ss, ss, ss.
Phenotypically, 50% of the progeny are smooth peas while 50% are wrinkled.
Looking at the population of each of the phenotype resulting from the cross. 252:247 is approximately a 50:50 ratio.
Hence, the genotypes of the two parents are Ss and ss.
I believe the blank is "mass."
I think it’s erosion... not sure what you’re asking
