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densk [106]
3 years ago
9

1/2(4-+6x)=1/3x+2/3(x+9)

Mathematics
1 answer:
KonstantinChe [14]3 years ago
8 0

Answer:

The value of x for the expression is 2

Step-by-step explanation:

Given algebraic expression as :

\frac{1}{2}(4 + 6 x ) = \frac{1}{3} x + \frac{2}{3} ( x + 9 )

Now, solving the given expression

Or, \frac{1}{2} × 4 + \frac{1}{2} × 6 x = \frac{1}{3} x + \frac{2}{3} x + \frac{2}{3} × 9

Or,  \frac{4}{2}  + \frac{6}{2} × x = \frac{1}{3} x + \frac{2}{3} x + \frac{18}{3}

or, 2 + 3 × x = \frac{x}{3} + \frac{2 x}{3}  + 6

or, 2 + 3 × x =  \frac{2 x + x}{3}  + 6

or, 2 + 3 × x = \frac{3 x}{3}  + 6

Or, 2 + 3 × x = x + 6

or, 3 x - x =  6 - 2

Or, 2 x = 4

∴  x = \frac{4}{2}

I.e x = 2

Hence The value of x for the expression is 2 Answer

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The mean spent on lottery tickets is normally distributed with a mean of $6.50 and a standard deviation of $2.25. If one custome
Natasha_Volkova [10]
First, we have to find the z scores of $4 and $9.50.
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3 years ago
A coordinate grid showing Number of Classes on the horizontal x-axis and Total Cost in dollars on the vertical y-axis with 2 lin
Oksana_A [137]

The system of equations representing these costs are; y = 7.5x and y = 5.5x + 10

<h3>How to find the equation of a line?</h3>

The slope of the first line is;

m = (y2 - y1)/(x2 - x1)

m = (32 - 10)/(4 - 0)

m = 5.5

Now, the first coordinate has a y-intercept of 10. Thus, the equation here for the cost is; y = mx + c = 5.5x + 10

The slope of the second line is;

m = (y2 - y1)/(x2 - x1)

m = (15 - 0)/(2 - 0)

m = 7.5

Now, the first coordinate has a y-intercept of 0. Thus, the equation here for the cost is; y = mx + c = 7.5x + 0 = 7.5x

Thus, the system of equations representing these costs are;

y = 7.5x and y = 5.5x + 10

Read more about Equation of a line at; brainly.com/question/13763238

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5 0
2 years ago
The sum of two numbers is ten. the difference between them is 8 . find the two numbers
alexira [117]

x+y=10

x-y=8, x=y+8

y+8+y=10

2y=2

y=1

So, x=10-y=10-1=9.

Numbers Would be 9 and 1.


3 0
3 years ago
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