3 years ago

Find the probability that a point chosen at random will lie in the shaded region.

Mathematics

1 answer:

malfutka [58]3 years ago

5 0

Step-by-step explanation:

In the 1st question

Total boxes = 6

Shaded boxes = 2

Probability = 2/6 = 1/3

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Describe two ways to solve the equation 2(4x-11)=10

shtirl [24]

2(4x-11) = 10

On dividing 2 on both sides

$\frac{2(4x-11)}{2} = \frac{10}{2}$

$4x-11 = 5$

On Adding 11 on both sides:

$4x-11+11 = 11+5$

$4x = 16$

On dividing both side by 4

$\frac{4x}{4} = \frac{16}{4}$

$x = 4$

Second way is:

We can use distributive property as

$2(4x-11) = 10$

$2*4x- 2*11 = 10$

$8x - 22 = 10$

On Adding 22 on both side

$8x - 22+22 = 10+22$

$8x = 32$

On dividing both side by 8

$\frac{8x}{8} = \frac{32}{8}$

$x = 4$

6 0

3 years ago

If a = 20 mm, b = 12 mm, and m∠C = 80°, what is the approximate area of ABC?

Lana71 [14]

Answer:

118.18 mm^2

Step-by-step explanation:

Sides <em>a</em> and <em>b</em> form angle C, so the information given is a side-angle-side (SAS) problem.

Use the formula $A=\frac{1}{2}ab\sin{C}$ .