Answer:
I think it would be A
Step-by-step explanation:
Answer:
x = 0 1 -1 -2
y = -3 -4 -2 -1
Step-by-step explanation:
equation : 3y+9x = -9
when x = 1
3y+3x = -9
or, 3y + 3×1= -9
or, 3y+3=-9
or, 3y = -12
so, y = -4
Again
Let's suppose x as -1
3y+3x= -9
or, 3y+ 3×-1 = -9
or, 3y-3 = -9
or, 3y = -6
y = -2
Let's suppose x as -2 now,
3y+3x = -9
3y+3×-2 = -9
or, 3y-6 = -9
or, 3y = -3
so, y = -1
A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
<span>L the length W the width
The length of a rectangle is 5 more than twice the width</span>
L = 5+ 2W
<span>the perimeter is equal the sum of sides =130
</span>
L+L+W+W =130
by subtitution we replace L by <span>L = 5+ 2W
</span>5+ 2W+<span>5+ 2W +W+W = 130
</span>
6W= 120
w= 20 <span>L = 5+ 2W= 5+ 40=45</span>
