Answer:
m ∠RMK = 51°
Step-by-step explanation:
m ∠JMK = m ∠RMK + m ∠JMR
10x + 19 = 7x - 26 + 6x + 12
10x +19 = 13x -14
19 = 3x -14
33 = 3x
11 = x
m ∠RMK = 7(11) - 26 = 51°
m ∠JMR = 6 (11) + 12 = 78
Answer:
The answer is True.
Step-by-step explanation:
- <u>Estimate the Answer Before Solving Having a general idea of a ballpark answer .</u>
- <u>Or the problem lets students know if their actual answer is reasonable or not.</u>
H = 11.81 m
v= π r2 h
h = v/ π r2 = 95/ π 1.6(2)* = 11.81228m or just 11.81
*(2) is squared
hope this helped haha
Answer:
1
Step-by-step explanation:
1. Convert the mixed number to an improper fraction to match the rest of the problem (this just makes it easier for now, the answer will still be a mixed number)
-1
becomes 
2. Re-write the new equation. When there is a "+" in front of a set of parentheses the expression doesn't change aside from removing the plus signs.
The new equation becomes
3. Calculate. Just work out the new expression.
The answer is 
4. Convert to a simplified mixed decimal.
27 goes into 20 once with seven left over, making the answer 1
<h3>
Answer: Approximately 13 square units (choice B)</h3>
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Explanation:
The given reflex angle is 215 degrees. A reflex angle is anything over 180 degrees, but less than 360. Subtract 215 from 360 to get the measure of angle AOB
angle AOB = 360 - 215 = 145
angle AOB = 145 degrees
We'll use this later.
Now find the area of the full circle. Use the formula A = pi*r^2. The radius is r = sqrt(10) which can be found through the distance formula or the pythagorean theorem. You want to find the length of either OA or OB to get the radius.
The area of the circle is
A = pi*r^2
A = pi*(sqrt(10))^2
A = 10pi
This is the exact area of the full circle, but we want just a fractional portion of it. Specifically we want the pie slice that is formed by angle AOB
area of sector AOB = [ (angle AOB)/360 ] * (area of full circle)
area of sector AOB = (145/360)*10pi
area of sector AOB = 145pi/36
area of sector AOB = 145*3.14/36
area of sector AOB = 12.647 approximately
area of sector AOB = 13 square units approximately, after rounding to the nearest whole number
