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bagirrra123 [75]
4 years ago
9

1 HELP PLEASE I'LL GIVE BRAINLIST AND POINTS!!!

Physics
1 answer:
mixas84 [53]4 years ago
4 0

Explanation:

The question of analog vs. digital audio is one of the more hotly debated questions in the world of music, film and media today. Does digital sound better? Does analog sound better? Is there even a noticeable difference?

It’s impossible to understand the difference completely without understanding what distinguishes analog audio from digital audio. A full discussion of these terms is best left to your curriculum and discussions with your mentor in the studio. For now, though, here’s a brief explanation of what these two words mean, and the differences between them.

Analog refers to a continuously changing representation of a continuously variable quantity. Digital, however, refers to representing these variable quantities in terms of actual numbers, or digits. The last two sentences seem a bit complex, but let’s try to simplify them with an example. If you consider the numbers 1 and 2 on a number line, there are actually an infinite number of points between 1 and 2. This is what analog represents—the infinite number of possibilities between 1 and 2. Digital, on the other hand, only looks at certain number of fixed points along the line between 1 and 2 (for example, 1 ¼, 1 ½, 1 ¾, and 2).

Can you see the difference? Digital takes a few “snapshots” of the number line, while analog takes the whole line into account.

As another example, think of analog vs. digital as the difference between seeing something in real life and watching it on film. When we see something happen in real life, there are no “spaces” between what we see, so we’re watching it happen in analog. Film, however, is actually a series of still photographs that are taken in rapid-fire intervals, and when we see them in succession, it tricks our minds into thinking we’re seeing a continuous flow of movement. So in a manner of speaking, when we watch the event happen on film, we’re watching it digitally, because we’re watching increments of the event, rather than the whole thing in fluid motion. (Not to be confused with digital video vs. film, which is another discussion completely!)

Let’s bring this idea into audio, music, and the studio. Sound occurs naturally in analog–that is to say, sound occurs in a continuous set of waves that we hear with the human ear. (Think of it as a “wavy” line with an infinite number of points along it.) When we capture that sound in a way that represents all the possible frequencies, we’re recording in analog; when we use computers to translate the sound into a series of numbers that approximate what we’re hearing, we’re recording in digital.

Thus, a purely analog recording would be something that was recorded on tape and produced using manual equipment to mix, master and press into a vinyl LP. A purely digital recording would be recorded on a computer program such as Pro Tools, mixed, mastered and produced digitally, and eventually burned onto a CD as an MP3 or audio file.

The most ironic aspect of the debate about digital vs. analog recording is that nowadays a lot of music is a combination of the two.  For example, you might record a song onto analog tape, but mix and master it digitally, or release it on the Internet as an MP3.

So what’s the difference in quality between analog and digital? The idea between digital recording is that our ears and brains technically can’t determine the spaces between the digital values, just like our brains interpret film as continuous motion. However, to many people, analog sound tends to be warmer, has more texture and is thought to capture a truer representation of the actual sound. Digital is felt to be somewhat cold, technical and perhaps lacking in analog’s nuance.

However digital is much cheaper. Recording an album with analog technology can require a whole studio full of equipment, but with digital recording technology, it’s possible to record a whole album in a bedroom on a laptop. And whereas analog technology can wear out or be damaged, digital media can last for an indefinite length of time.

Today many recording artists, both major and independent, record using a mixture of digital and analog techniques. While analog audio does give warmth and a truer sound quality, digital is cheaper to work with and offers more control over the finished product.

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Calculate the distance moved by a runner who runs with a speed of 5 km/h for a period of 1.5 hours.
FrozenT [24]

Answer:

7.5 km

Explanation:

h5 per hour means that he traveled 5 km in 1 our. And then half of the hour, which means half an hour 5 km which is 2.5.

5 + 2.5 = 7.5

or just 1.5 x 5 = 7.5

8 0
3 years ago
Stars produce their own light but planets do not. Even then we can see them. explain
PilotLPTM [1.2K]
Planets are not hot enough, and that's because they lack the internal energy sources that stars have: thermonuclear fusion (They do emit a little light, mainly infrared light, but nothing compared to the sun)

Planets don't have their own light, so simply they do not emit light, this phenomena goes back to their information. When they are formed, they are much, much less hotter than the stars. In stars, fusion reaction always goes on, in which energy, as well as light is formed, so, there is light for stars to emit for a long time.
4 0
4 years ago
Two hypothetical planets of masses m1 and m2 and radii r1 and r 2 , respectively, are nearly at rest when they are an infinite d
Leto [7]

Answer:

(a) v_1 = m_2\sqrt{\frac{2G}{d(m_1+m_2)} }

v_2=m_1\sqrt{\frac{2G}{d(m_1+m_2)} }

(b) Kinetic Energy of planet with mass m₁, is KE₁ =  1.068×10³² J

Kinetic Energy of planet with mass m₂, KE₂ =  2.6696×10³¹ J

Explanation:

Here we have when their distance is d apart

F_{1} = F_{2} =G\frac{m_{1}m_{2}}{d^{2}}

Energy is given by

Energy \,of \,attraction = -G\frac{m_{1}m_{2}}{d}}+\frac{1}{2} m_{1} v^2_1+ \frac{1}{2} m_{2} v^2_2

Conservation of linear momentum gives

m₁·v₁ = m₂·v₂

From which

v₂ =  m₁·v₁/m₂

At equilibrium, we have;

G\frac{m_{1}m_{2}}{d}} = \frac{1}{2} m_{1} v^2_1+ \frac{1}{2} m_{2} v^2_2       which gives

2G{m_{1}m_{2}}= d m_{1} v^2_1+  dm_{2} (\frac{m_1}{m_2}v_1)^2= dv^2_1(m_1+(\frac{m_1}{m_2} )^2)

multiplying both sides by m₂/m₁, we have

2Gm^2_{2}}= dv^2_1 m_2+dm_1v^2_1 =dv^2_1( m_2+m_1)

Such that v₁ = \sqrt{\frac{2Gm^2_2}{d(m_1+m_2)} }

v_1 = m_2\sqrt{\frac{2G}{d(m_1+m_2)} }

Similarly, with v₁ =  m₂·v₂/m₁, we have

G\frac{m_{1}m_{2}}{d}} = \frac{1}{2} m_{1} v^2_1+ \frac{1}{2} m_{2} v^2_2\Rightarrow  2G{m_{1}m_{2}}= dm_{1} (\frac{m_2}{m_1}v_1)^2 +d m_{2} v^2_2= dv^2_2(m_2+(\frac{m_2}{m_1} )^2)

From which we have;

2G{m^2_{1}}= dm_{2} v_2^2 +d m_{1} v^2_2 and

v_2=m_1\sqrt{\frac{2G}{d(m_1+m_2)} }

The relative velocity = v₁ + v₂ =v_1+v_2=m_1\sqrt{\frac{2G}{d(m_1+m_2)} } + m_2\sqrt{\frac{2G}{d(m_1+m_2)} } = (m_1+m_2)\sqrt{\frac{2G}{d(m_1+m_2)} }

v₁ + v₂ = (m_1+m_2)\sqrt{\frac{2G}{d(m_1+m_2)} }

(b) The kinetic energy KE = \frac{1}{2}mv^2

KE_1= \frac{1}{2} m_{1} v^2_1 \, \, \, KE_2= \frac{1}{2} m_{2} v^2_2

Just before they collide, d = r₁ + r₂ = 3×10⁶+5×10⁶ = 8×10⁶ m

v_1 = 8\times10^{24}\sqrt{\frac{2\times6.67408 \times 10^{-11}} {8\times10^6(2.00\times10^{24}+8.00\times10^{24})} } = 10333.696 m/s

v_2 = 2\times10^{24}\sqrt{\frac{2\times6.67408 \times 10^{-11}} {8\times10^6(2.00\times10^{24}+8.00\times10^{24})} } =2583.424 m/s

KE₁ = 0.5×2.0×10²⁴× 10333.696² =  1.068×10³² J

KE₂ = 0.5×8.0×10²⁴× 2583.424² =  2.6696×10³¹ J.

7 0
3 years ago
Define equilibrium and explain first condition of equilibrium. Pease make it fast...
Semenov [28]

Answer:

First Condition of Equilibrium

For an object to be in equilibrium, it must be experiencing no acceleration. This means that both the net force and the net torque on the object must be zero. Here we will discuss the first condition, that of zero net force. ... Fnet=0 F net = 0.

4 0
3 years ago
a 5 charge is locataed 1.25 m to the left of a -3 charge. What is the magnitude and direction of the electrostatic force on the
Alika [10]

Answer:

The force is 86.5×10^9 N towards the negative charge (to the right)

Explanation:

The electrostatic force on the charges is given by Coulomb's law;

F= Kq1q2/r^2

This an inverse square law.

F= electrostatic force on the charges

K= constant of Coulomb's law

q1 and q2= magnitude of the charges

Since K= 9.0×10^9Nm^2C^2

F= 9.0×10^9 × 5 × 3/(1.25)^2 = 135×10^9/1.56

F= 86.5×10^9 N

The force is 86.5×10^9 N towards the negative charge.

5 0
3 years ago
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