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mr Goodwill [35]
3 years ago
15

A particle moving along the y-axis has the potential energy u =4y3j, where y is in m. what is the y-component of the force on th

e particle at y=0 m, 1 m, and 2 m?
Physics
1 answer:
Ivenika [448]3 years ago
7 0

Potential energy is given as

U = 4y^3

now as we know that force is related by potential energy by the formula

F = - \frac{dU}{dy}

So it is gradient of energy with position in Y

F = - \fracd(4y^3}{dy}

F = -12y^2 \hat j

Now at y = 0

F = 0 N

at y = 1

F = - 12*1^2

F = - 12 N

at y = 2

F = - 12*2^2

F = - 48 N

so above is the forces at given positions

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