The angle theta of the spring is 31 degrees. To solve for this, show the equation which is equal to the 10lb ball. With this, the unknown will be the angle. Then transpose/transfer the terms in order to isolate the variable for the angle. First solve for s, then solve for angle theta. You will come up with s = .5849 ft and angle theta = 31.2629 or 31 degrees. Hope this helps.
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<u>We are given:</u>
Initial velocity (u) = 32 m/s
Acceleration (a) = 3 m/s²
Displacement (s) = 40 m
Final Velocity (v) = v m/s
<u>Solving for the Final Velocity:</u>
from the third equation of motion:
v² - u² = 2as
<em>replacing the variables</em>
v² - (32)² = 2(3)(40)
v² = 240 + 1024
v² = 1264
v = √1264
v = 35.5 m/s
Therefore, the velocity of the bike after travelling 40 m is 35.5 m/s
Answer:
Simply divide the kgm/s by the 5kg
35kgm/s ÷ 5.0kg = 7m/s
