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3 years ago

14

If forces acting on an object are unbalanced, the object could experience a change in ________. mass, speed, or direction negati

ve acceleration or mass direction, mass, or both speed, direction, or both

2 answers:

k0ka [10]3 years ago

6 0

Answer:

D

Explanation:

speed, direction, or both

jeyben [28]3 years ago

5 0

Answer:

speed, direction, or both

Explanation:

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A girl is out jogging at 2.00 m/s and accelerates at 1.50 m/s^2 until she reaches a velocity of 5.00 m/s. How far does she get?

Maksim231197 [3]

Answer:

7.00 m

Explanation:

Given:

v₀ = 2.00 m/s

v = 5.00 m/s

a = 1.50 m/s²

Find: Δx

v² = v₀² + 2aΔx

(5.00 m/s)² = (2.00 m/s)² + 2(1.50 m/s²)Δx

Δx = 7.00 m

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3 years ago

A uniform disk of mass m = 2.4 kg and radius R = 25 cm can rotate about an axle through its center. Four forces are acting on it

Zinaida [17]

Answer:

0 Nm

Explanation:

Torque is the cross product of the radius vector and the force vector.

τ = r × F

In other words, the magnitude of the torque is equal to the magnitude of the radius times the magnitude of the force times the sine of the angle between them.

τ = rF sin θ

Since F₃ is parallel to the radius vector, θ = 0, so τ = 0.

6 0

4 years ago

A cubical box measuring 1.29 m on each side contains a monatomic ideal gas at a pressure of 2.0 atm How much thermal energy do t

Marrrta [24]

Answer:

a) $U = 652.545\,kJ$ , b) $v \approx 659.568\,\frac{m}{s}$

Explanation:

a) According to the First Law of Thermodinamics, the system is not reporting any work, mass or heat interactions. Besides, let consider that such box is rigid and, therefore, heat contained inside is the consequence of internal energy.

$Q = U$

The internal energy for a monoatomic ideal gas is:

$U = \frac{3}{2} \cdot n \cdot R_{u} \cdot T$

Let assume that cubical box contains just one kilomole of monoatomic gas. Then, the temperature is determined from the Equation of State for Ideal Gases:

$T = \frac{P\cdot V}{n\cdot R_{u}}$

$T = \frac{(202.65\,kPa)\cdot(1.29\,m)^{3}}{(1\,kmole)\cdot(8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K} )}$

$T = 52.325\,K$

The thermal energy contained by the gas is:

$U = \frac{3}{2}\cdot (1\,kmole)\cdot (8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K})\cdot (52.325\,K)$

$U = 652.545\,kJ$

b) The physical model for the cat is constructed from Work-Energy Theorem:

$U = \frac{1}{2}\cdot m_{cat} \cdot v^{2}$

The speed of the cat is obtained by isolating the respective variable and the replacement of every known variable by numerical values:

$v = \sqrt{\frac{2 \cdot U}{m_{cat}}}$

$v = \sqrt{\frac{2\cdot (652.545 \times 10^{3}\,J)}{3\,kg} }$

$v \approx 659.568\,\frac{m}{s}$

3 0

3 years ago

A zebra starts from rest and accelerates at 1.9 m/s2 what will be the acceleration after 5 seconds

Alex73 [517]

Answer:

d = 23.75 m

The zebra has gone 23.75m after 5 seconds.

Corrected question;

A zebra starts from rest and accelerates at 1.9 m/s2. How far has the zebra gone after 5 seconds.

Explanation:

From the equation of motion;

d = vt + 0.5at^2 .........1

Where;

d = displacement

v = initial velocity = 0

t = time taken= 5 seconds

a = acceleration = 1.9 m/s^2

Substituting the given values into equation 1;

d = 0(5) + 0.5(1.9×5^2)

d = 0.5(1.9×5^2)

d = 23.75 m

The zebra has gone 23.75m after 5 seconds.

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4 years ago

What a not an aspect of relative wind

daser333 [38]

Relative wind<span> is defined as the airflow relative to an airfoil.</span>

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3 years ago

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