All of these statements about flux are true, except for the last one - <span>When turning a surface inside of an electric field, the maximum flux is achieved if the electric field vector and the surface vector are perpendicular.
These vectors don't have to be perpendicular, which is why this statement is incorrect, whereas the rest of them are true. </span>
The answer is no. If you are dealing with a conservative force and the object begins and ends at the same potential then the work is zero, regardless of the distance travelled. This can be shown using the work-energy theorem which states that the work done by a force is equal to the change in kinetic energy of the object.
W=KEf−KEi
An example of this would be a mass moving on a frictionless curved track under the force of gravity.
The work done by the force of gravity in moving the objects in both case A and B is the same (=0, since the object begins and ends with zero velocity) but the object travels a much greater distance in case B, even though the force is constant in both cases.
Pretty fast. Everything looks fast when running past a light pole
Answer:
True
Explanation:
Because I had a test on this