Answer:
The answer is given below <3
Step-by-step explanation:
The options are not given but I would list the inequalities needed to solve this problem.
As a result of increase in people to attend meeting, the number of sushi needed to be ordered is 100 pieces. Sofia has already ordered 24 pieces. If R is the number of additional rolls that Sofia orders.
The number of additional rolls that Sofia orders (R) must be greater than or equal to the difference between the number of Sushi needed to be ordered and the number of Sushi that has already being ordered. It is given by the inequality:
R ≥ 100 - 24
R ≥ 76
If each roll contains 12 pieces, the number of rolls needed (n) is given by:
n ≥ R/12
n ≥ 76/12
n ≥ 6.33
n ≥ 7
If each roll cost $8, the money needed to buy the sushi is given as:
Cost ≥ 8(7) ≥ $56
Answer:
x < -6
Step-by-step explanation:
-4x - 5 > 19
+5 +5
-------------------
-4x > 24
/-4 /-4
-------------------
x < -6
The least common multiple of 32 and 80 is 160.
Answer:
20x + 41y
Step-by-step explanation:
<span><span>1.
</span>The music hall has 20 boxes :
=> on thurs 2/5 were occupied
=> on friday 2/4 were occupied
=> and on saturday 8/10 were occupied.
Let’s find out which day has the most occupied space of the music hall.
2/5 + 2/4 + 8/10 = 6/20 + 7/20 + 10/20
Thurs 2/5 were occupied
=> 6/20 = 0.3
=> 20 * 0.3 = 6 boxes
Friday 2/4 were occupied
=> 7/20 = 0.35
=> 20 * 0.35 = 7 boxes
Saturday 8/10 were occupied.
=> 10/20 = 0.5
=> 20 * .5 = 10 boxes
Thus, during Saturday has the most number of occupied boxes.</span>
