My guess would be Probability
Answer: FIRST OPTION
Step-by-step explanation:
<h3>
The missing picture is attached.</h3>
By definition, given a Quadratic equation in the form:
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.
The Quadratic Formula is the following:
![x=\frac{-b \±\sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%20%5C%C2%B1%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D)
In this case, the exercise gives you this Quadratic equation:
![5x^2 + 3x - 4 = 0](https://tex.z-dn.net/?f=5x%5E2%20%2B%203x%20-%204%20%3D%200)
You can identify that the numerical coefficients are:
![a=5\\\\b=3\\\\c= - 4](https://tex.z-dn.net/?f=a%3D5%5C%5C%5C%5Cb%3D3%5C%5C%5C%5Cc%3D%20-%204)
Therefore, you can substitute values into the Quadratic formula shown above:
![x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%20%5C%C2%B1%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B-3%20%5C%C2%B1%5Csqrt%7B%283%29%5E2-4%285%29%28-4%29%7D%20%7D%7B2%285%29%7D)
You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.
Fifi should put 13/24 cups of sugar in each bowl.
3 divided by 6 = 1/2
1/4 divided by 6 = 1/24
1/2 + 1/24 = 12/24 + 1/24 = 13/24
Answer:
<h2>y = 9</h2>
Step-by-step explanation:
Put x = 5 to the equation -6x - 3y = -57
(-6)(5) - 3y = -57
-30 - 3y = -57 <em>add 30 to both sides</em>
-3y = -27 <em>divide both sides by (-3)</em>
y = 9
Answer:
Step-by-step explanation:
The volume of a cylinder is
![V=\pi r^2h](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E2h)
We are given a diameter of 5, which means that the radius is 2.5. The height is 15. Filling in:
![V=\pi(2.5)^2(15)](https://tex.z-dn.net/?f=V%3D%5Cpi%282.5%29%5E2%2815%29)
which gives you, in terms of π:
V = 93.75π in³ or if you are multiplying in π,
V = 294.5 in³