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Effectus [21]
3 years ago
14

Which statements describe a parallelogram that must be a rectangle? Select each correct answer. parallelogram with opposite side

s congruent parallelogram with a right angle parallelogram with congruent diagonals parallelogram with perpendicular diagonals parallelogram with a pair of congruent consecutive sides
Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0

The following statements are true for a parallelogram that must be a rectangle.

parallelogram with a right angle

parallelogram with congruent diagonals

A Parallelogram is a flat shape with opposite sides parallel and equal in length. Squares, rectangles and rhombuses are all parallelograms but with slight differences.

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Fill in the blank with the correct response.
I am Lyosha [343]

Answer:

In a standard normal distribution

95% of the data is within 2 standard deviations of the mean.

have a nice day! (^o^)

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3 years ago
School A and B are competing in an academic contest. at the beginning of the final round, school A has 174 points and school B h
zhenek [66]

Answer:

Step-by-step explanation:

First add 11 then -69

4 0
3 years ago
Read 2 more answers
Jamal wants to find the sum of 6/10 and 17/100. He says the sum is twenty-three hundreths. What was his mistake?
Veseljchak [2.6K]
His mistake is he didn't make 6/10 to 60/100 he added them without changing the 6/10
5 0
3 years ago
Factor the polynomial
Anettt [7]

Answer:

(3x + 5)(9x^2 - 15x + 25)

Step-by-step explanation:

27x^3 + 125

= (3x)^3 + 5^3

= (3x + 5) ((3x)^2 - (3x)(5) + 5^2)

= (3x + 5)(9x^2 - 15x + 25)

FYI: a³ + b³ = (a + b)(a² – ab + b²)

8 0
2 years ago
Read 2 more answers
Which graph represents the solution to the system of inequalities? x + y ≥ 4 2x + 3y < 12
viktelen [127]
There are two inequality equations to be graphed:

<span>x + y ≥ 4
2x + 3y < 12

For the first step, let's disregard the inequality symbols and take it like any conventional algebraic equation. This is to be able to graph the lines on a Cartesian planes first.

For the first equation, x+y=4. To find the x- and y-intercepts, let the other variable be 0. For example,
x-intercept:
x+0=4
x=4
y-intercept:
0+y=4
y=4
Therefore, you can graph the equation line by plotting the intercepts (4,0) and (0,4) and connecting them together. The same thing is done to the second equation:
x-intercept: 
</span>2x + 0 = 12
x=12/2=6
y-intercept:
0 + 3y =12
y= 12/3 = 4
Therefore, you can graph the equation line by plotting the intercepts (6,0) and (0,4) and connecting them together. The graph is shown in the left side of the picture.

The next step would be testing the inequalities. Let's choose a point that does not coincide with the lines. That point could be (-5,-1). 

x + y ≥ 4
-5 + -1 ≥4
-6 ≥ 4 --> this is not true. Thus, the solution of the graph must not include the area of this point. It includes everything to the right of the line denoted by the blue-shaded region.

2x + 3y < 12
2(-5) + 3(-1) <12
-13 < 12 ---> this is true. Thus, the solution would include this point. That includes all points to the left of the orange line denoted by the orange-shaded the region.

The region where blue and orange overlap is the solution of the system of equations, denoted by the green-shaded region.

3 0
3 years ago
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