Answer:
45, 000 J o 45 KJ
Step-by-step explanation:
Recordemos que trabajo realizado = fuerza * distancia
En este caso, fuerza = peso del objeto
Por lo tanto, peso del objeto = 180 Kg * 10ms ^ 2 = 1800 N
Por eso;
Trabajo realizado = 1800 N * 25 m = 45, 000 J o 45 KJ
<u>Let's take this problem step-by-step</u>:
<u>The ;unlabeled angle' adjacent to the 'outside angle of measure 78°'</u>
⇒ is on a straight line
⇒ sum of angle measure = 180 degrees

<u>Now we know:</u>
⇒ sum of all angles in a triangle ⇒ 180°
<u>Let's put that in equation form and solve:</u>

<u>Answer: 21°</u>
<u></u>
Hope that helps!
#LearnwithBrainly
To solve this we are going to use the half life equation

Where:

is the initial sample

is the time in years

is the half life of the substance

is the remainder quantity after

years
From the problem we know that:



Lets replace those values in our equation to find

:




We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be
91.7 grams.