Answer:
y=-x+8
Step-by-step explanation:
First distribute the negative
2y=(-x+4)2+8
then you would multiply the (-x+4) by the two
2y=-2x+8+8
then you would combined like terms
2y=-2x+16
then you would divide both sides by 2
y=-x+8
When evaluating b^2c^-1 for b=8 and c=4, the answer is -16
E = b^2c–1
x-a = 1/xa
E = b^2c - 1
= 8^2 x (-4)-1
= 64/-4
= -16
Answer: (16/25)
Step-by-step explanation: That's -(4/5) x -(4/5) = (16/25). It's that answer because a negative times a negative equals a positive. The exponent in the problem is telling you to multiply -4/5 times itself 2 times.
A) Tangent is positive in Quadrant I.
Since sine and cosine are both positive in Quadrant I and tangent is the ratio of sine to cosine, tangent is positive in Quadrant I
![\sf{14(\sqrt[3]{x}) }](https://tex.z-dn.net/?f=%5Csf%7B14%28%5Csqrt%5B3%5D%7Bx%7D%29%20%7D)
Step-by-step explanation:
![5(\sqrt[3]{x})+9(\sqrt[3]{x})\\\\(5+9)(\sqrt[3]{x})\\\\14(\sqrt[3]{x})](https://tex.z-dn.net/?f=5%28%5Csqrt%5B3%5D%7Bx%7D%29%2B9%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C%285%2B9%29%28%5Csqrt%5B3%5D%7Bx%7D%29%5C%5C%5C%5C14%28%5Csqrt%5B3%5D%7Bx%7D%29)
