Answer:
a. withdraws electrons inductively
b. donates electrons by hyperconjugation
c. donates electrons by resonance
d. withdraws electrons inductively
Explanation:
a. The bromide ion is a highly electronegative ion (in the halide series). Electronegative substituents on acids increase the acidity by inductive electron withdrawal method. The higher the electronegativity of a substance, the greater the acidity. The halogens have this order of electronegativity:
F > Cl > Br>I
b. The carboxyl groups have a stabilization of the sigma and pi bonds. This is achieved through a special delocalization of electrons. Because of the delocalization, hyperconjugation is the result effect.
c. The NHCH₃ group has a highly electonegative nitrogen atom that pulls the electron cloud towards itself. In this case, it withdraws electrons inductively. As a result, it donates electrons by resonance.
d. The OCH₃ group has a highly electonegative oxygen atom. This oxygen atom withdraws electron cloud towards itself. As a result, it withdraws electrons inductively.
Answer:
5.38 moles of CO₂ are produced
Explanation:
This is the reaction:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
First of all, let's convert the mass of C₃H₈ to moles (mass / molar mass)
79 g / 44 g/mol = 1.79 moles
So ratio is 1:3.
1 mol of C₃H₈ is needed to produce 3 moles of CO₂
1.79 moles of C₃H₈ would produce (1.79 .3) /1 = 5.38 moles
Could you provide us with a picture of the moon phase please?
Answer:
Increase in height from the ground.
Explanation:
Potential energy =mass×acceleration due to gravity×height.
P.E= mgh