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ivolga24 [154]
3 years ago
13

How many moles of O2 molecules should be supplied to burn 1 mol of CH4 molecules in a domestic furnace?

Chemistry
1 answer:
Sati [7]3 years ago
4 0
The combustion of 1 mole of methane (CH4) in a domestic furnace requires 2 moles of O2 molecules, assuming the combustion was complete or ideal. To solve this problem, use stoichiometry of the reaction's balanced chemical equation:

CH4 + 2O2 --> CO2 + 2H2O

The ratio of CH4 to O2 in terms of moles is 1:2. So 1 mole of CH4 needs 2 moles of O2.
You might be interested in
Which scale is being described? Water freezes at 32. Water freezes at 0. Water freezes at 273.
Leya [2.2K]

Scale is defined as the measurement of unit ranges, that has been corresponds to the measurements.

The units for the measurement of temperature are given as:

\rm 0^\circ C\;=\;273\;K\;=\;32\;F

<h3>Which scale is used?</h3>

The scale used for the measurement of the freezing is the temperature scale. The temperature is measured in the units of Kelvin, Fahrenheit , and Celsius.

The unit scale for the measurement of freezing of water are

  • Freezes at 32 -  In the Fahrenheit scale
  • Freezes at 0 - In the Celsius scale
  • Freezes at 273 - In the Kelvin scale

Learn more about measurement scale, here:

brainly.com/question/1152255

7 0
2 years ago
The correct answer for the addition of 5.8 g + 2.26g + 1.311g + 2 g is?
jeka94

Answer:

= 11.371g

Explanation:

Hope This Helps! :]

4 0
3 years ago
In this model of a molecule of ammonia, nh3, how many covalent bonds are represented? ammonia
motikmotik
I don't know but I would pick b.2.covalent bonds
6 0
3 years ago
Help this is my test
miss Akunina [59]

Answer:

the answer is v and z. you can see the pic

7 0
3 years ago
Read 2 more answers
A 7.5 L cylinder contains 5 moles of gas at a temperature of 274°C. What is its pressure in kiloPascals (kPa)?
AleksAgata [21]
<h3><u>Answer;</u></h3>

 = 3032.15 kPa

<h3><u>Explanation;</u></h3>

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Volume = 7.5 L, T = 274 +273 = 547 K, N = 5 moles

Therefore;

Pressure = nRT/V

               = (5 × 0.08206 × 547)/7.5 L

               = 29.925 atm

But; 1 atm = 101325 pascals

Hence; Pressure = 3032150.63 pascals

                            <u>= 3032.15 kPa</u>

               

3 0
3 years ago
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