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ivolga24 [154]
3 years ago
13

How many moles of O2 molecules should be supplied to burn 1 mol of CH4 molecules in a domestic furnace?

Chemistry
1 answer:
Sati [7]3 years ago
4 0
The combustion of 1 mole of methane (CH4) in a domestic furnace requires 2 moles of O2 molecules, assuming the combustion was complete or ideal. To solve this problem, use stoichiometry of the reaction's balanced chemical equation:

CH4 + 2O2 --> CO2 + 2H2O

The ratio of CH4 to O2 in terms of moles is 1:2. So 1 mole of CH4 needs 2 moles of O2.
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When two ions form an ionic bond, what type of compound is formed?
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it is c. ionic compound just because it says ionic. can't be a crystal since there's no links to an ionic bond connected to crystals (and if it were it'd depend on the elements and the thingy majig itself right) and a covalent bond is an entirely different bond which isn't related to ionic. hope this helped, and i hope you have a good day too! :D

3 0
2 years ago
True or false:The nucleus is the largest part of the atom and takes up most space
alexira [117]
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5 0
3 years ago
What observation did Rutherford make from his gold-foil experiment which
JulsSmile [24]

Answer:

A piece of gold foil was hit with alpha particles, which have a positive charge. Most alpha particles went right through. This showed that the gold atoms were mostly empty space. Some particles had their paths bent at large angles. A few even bounced backward. The only way this would happen was if the atom had a small, heavy region of positive charge inside it.

8 0
2 years ago
You have 20 g of a buckyball (C20) .
gregori [183]
The answer is 0.08 mol
3 0
2 years ago
∆G° for the process benzene (l) benzene (g) is 3.7 Kj/mol at 60 °C , calculate the vapor pressure of benzene at 60 °C [R=0.0821
Alex787 [66]

Answer:

4) 0.26 atm

Explanation:

In the process:

Benzene(l) → Benzene(g)

ΔG° for this process is:

ΔG° = -RT ln Q

<em>Where Q = P(Benzene(g)) / P°benzene(l) P° = 1atm</em>

ΔG° = 3700J/mol = -8.314J/molK * (60°C + 273.15) ln P(benzene) / 1atm

1.336 = ln P(benzene) / 1atm

0.26atm = P(benzene)

Right answer is:

<h3>4) 0.26 atm </h3><h3 />
6 0
2 years ago
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