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3 years ago

Question 16 (3 points)

Chemistry

2 answers:

Hitman42 [59]3 years ago

6 0

Answer:

halogens and noble gases

Explanation:

group VIIA (17) of the periodic table are the halogens and group VIIIA (18) of the periodic table are the noble gases

the p-orbital block is from group 13 to group 18

igor_vitrenko [27]3 years ago

5 0

Unless otherwise instructed, you may use the periodic table in the Chemistry: Problems and Solutions book for this test.

Which element has the greatest first ionization energy?

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How many molecules of CH4 are in 48.2 g of this compound? A) 2.00 x 1023 B) 5.00 x 10-24 C)1.81 x 1024 D) 4.00 E) 4.64 x 1026 10

Tasya [4]

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of methane = 48.2 g

Molar mass of methane = 16 g/mol

Putting values in above equation, we get:

$\text{Moles of }CH_4=\frac{48.2g}{16g/mol}=3.0125mol$

According to mole concept:

1 mole of compound contains $6.022\times 10^{23}$ number of molecules.

So, 3.0125 moles of methane will contain = $3.0125\times 6.022\times 10^{23}18.141\times 10^{23}=1.81\times 10^{24}$ number of molecules.

Hence, the correct answer is Option C.

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3 years ago

((Please help asap! Giving brainliest))

astraxan [27]

i hope this helped!

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4 years ago

Read 2 more answers

Which of the following reagents convert(s) benzoyl chloride to phenyl propyl ketone?a. CH3CH2CH2MgBrb. CH3CH2CH2Lic. (CH3CH2CH2)

Gelneren [198K]

Answer:C

(CH3CH2CH2)2CuLi

Explanation:

The reaction between acyl halides and Grignard reagents or acyl halides and organolithium compounds does not form ketones because the reagents ( Grignard reagent and organo lithium compounds) are too reactive hence the ketone intermediate reacts further to form tertiary alcohols hence the ketone cannot be isolated.

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3 years ago

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Harlamova29_29 [7]

Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Explanation:

Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

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It is known that molarity is the number of moles of solute present in liter of a solution.

Therefore, moles present in given solution are calculated as follows.

$Molarity = \frac{moles}{Volume (in L)}\\0.750 M = \frac{moles}{0.085 L}\\moles = 0.0637 mol$

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

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Vladimir79 [104]

Answer:

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