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Alexxandr [17]
4 years ago
13

What caused wind to blow

Chemistry
2 answers:
Arlecino [84]4 years ago
7 0

Answer:

Different atmospheric pressure. When there is a different atmospheric pressure, air moves from the higher pressure to the lower pressure area which results in what you call <u>WIND</u> but can result in various speeds and pressure.

Hope this helped and if it did, please give my answer a brainliest.

maw [93]4 years ago
4 0

Answer:

Wind is caused by differences in the atmospheric pressure.

Explanation:

When a difference in atmospheric pressure exists, air moves from the higher to the lower pressure area, resulting in winds of various speeds.

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How do electrons differ from protons and neutrons? A. They do not move. B. They are larger. C. They are not in a fixed position.
nikdorinn [45]
Hi!

Electrons are particles which basically 'orbit' around the nucleus. Protons and neutrons are condensed, in a fixed position inside the nucleus. 

With this in mind, the answer will be C.

Hopefully, this helps! =)
4 0
3 years ago
Read 2 more answers
How do you preform water displacement
malfutka [58]
<span>1. Fill a beaker or graduated cylinder with enough water to completely immerse the sphere in. 2. Record the baseline initial measurement. 3. Drop the sphere in. 4 <span>Record final measurement.</span></span>
6 0
3 years ago
G you have 57.0 ml of a 0.400 m stock solution that must be diluted to 0.100 m. assuming the volumes are additive, how much wate
Amanda [17]
Answer:
added water = 171 ml

Explanation:
Assuming volumes are additive, the rule that we will use to solve this question is:
M1V1 = M2V2
where:
M1 is the initial concentration = 0.4 m
V1 is the initial volume = 57 ml
M2 is the final concentration = 0.1 m
V2 is the final volume that we want to calculate
Substitute with the given in the above equation to get V2 as follows:
M1V1 = M2V2
(0.4)(57) = (0.1)V2
22.8 = 0.1V2
V2 = 228 ml

Now, the final volume is equal to the initial volume plus the amount of added water. So, to get the amount of added water, we will subtract the initial volume from the final volume as follows:
V2 = V1 + added water
228 = 57 + added water
added water = 228 - 57 = 171 ml

Hope this helps :)
3 0
3 years ago
What happens to sodium sulphate in water​
kirza4 [7]

Answer:

It dissolves into the water

Na₂SO₄ + H₂O → 2Na₊_{aq} + SO₄²-_{aq}

Hope this helps :)

Have a great day !

5INGH

Explanation:

6 0
3 years ago
How many grams of KCl (s) has been produced from the thermal decomposition of KClO3 (s) that produced 50.0 mL of O2 (g) at 25 de
geniusboy [140]

Answer:

The mass is m_{KCl} =  0.102 \ g

Explanation:

From the question we are told that

   The volume of oxygen produced is  V_o = 50mL  = 50 *10^{-3} L

    The temperature is T = 25 ^oC = 25* 273 = 298 K

     The pressure is  P = 1.0\  atm

From the ideal gas law we have that

      PV =  nRT

Where R is the gas constant  with the value

         R =  0.08206 \ atm \cdot L /mol K

  n is the number of moles making it the subject of the formula

          n = \frac{PV}{RT}

Substituting values

          n = \frac{1 * (50 *10^{-3}) }{0.08206 * 298}

          n =  2.045 *10^{-3} \  mol

From the chemical equation

      one mole of  KClO_3 produces one mole of  kCl and   \frac{3}{2} of oxygen

       x mole of  KClO_3 produces x mole of  kCl and   2.045 *10^{-3} \  mol of oxygen

So    x = \frac{2.045 *10^{-3}}{\frac{3}{2} }

      x =  \frac{2}{3} * 2.045 *10^{-3}

      x =  1.363 *10^{-3} \ mol

Now the molar mass of  KCl is a constant with a value

           M_{KCl} = 74.55  g/mol

Now the mass of KCl is mathematically evaluated as

          m_{KCl} = x * M_{KCl}

Substituting values

          m_{KCl} = 1.363 *10^{-3} * 74.55

         m_{KCl} =  0.102 \ g

6 0
3 years ago
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