The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.
Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that
L = 2W - 5
Substituting L into P, we have
P = 2(2W - 5 + W)
P = 2(W - 5)
Since P = 56, we have
2(W - 5) = 56
~Dividing both sides by 2, we have
W - 5 = 56/2
W - 5 = 23
Adding 5 to both sides, we have
W = 23 + 5
W = 28 inches
Substituting W into L, we have
L = 2W - 5
L = 2(28) - 5
L = 56 - 5
L = 51 inches
So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Learn more about perimeter of a rectangle here:
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Answer:
Approximately 68%.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 1, standard deviation = 0.05.
Estimate the percent of pails with volumes between 0.95 gallons and 1.05 gallons.
0.95 = 1 - 0.05
1.05 = 1 + 0.05
So within 1 standard deviation of the mean, which by the Empirical Rule, is approximately 68% of values.
Answer:
12 = 12
Step-by-step explanation: equal integer theorem.
4cm I think, because it’s usually a even and equal number. But don’t take my word for it.
The answers is Rational. hope that helps