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Licemer1 [7]
3 years ago
10

Middle school help???? fast

Mathematics
2 answers:
klio [65]3 years ago
7 0

Answer:

8.4 ft

Step-by-step explanation:

Perimeter = side x 4

(Re-arrange)

Side = Perimeter / 4

34/4 = 8.4 ft

Free_Kalibri [48]3 years ago
7 0

Answer:

8.5 feet

Step-by-step explanation:

Divide 34 by 4. A square has 4 sides which are all the same.

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The value of a stock market decreases a total of 85 points over a 15 minute period of trading. How much does the stock value cha
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Answer:

-5 2/3 points per minute

Step-by-step explanation:

change / time = (-85 points)/(15 minutes) = -17/3 points/minute = -5 2/3 points/minute

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3 years ago
Rochelle works part-time at the college museum, which pays her at a rate of $10 per hour. She also makes small bracelets that sh
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We know for our problem that Rachel makes $10 per hour. Sincex represent the number of hours that she works,  10x will be the total amount that she will make for working x hours. We also know that she sells bracelets for $5 each. Since y represents the number of of bracelets that she sells, 5y will be her total revenue for selling y bracelets. We also know that she needs to earn at least $200 a week to cover her expenses, so the sum of 10x and 5y must be equal or greater than 200:

10x+5 \geq 200

We can conclude that <span>the graphs that shows the inequality that represents this situation, with its solution region shaded is:</span>

7 0
3 years ago
Given the following two side lengths of a triangle, what is the largest whole number length
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3 0
2 years ago
Vaimiti walks at a constant pace of 1.1 m/s and takes 25 minutes to get to school.
Temka [501]

Solution:

<u>Note that:</u>

  • Speed = Distance/Time
  • Vaimiti speed = 1.1 m/s
  • Jabril speed = 1.3 m/s

<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>

  • Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
  • => Vaimiti's time to reach school: 1500 seconds

<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>

  • Jabril's time to reach school: 30 minutes = 30 x 60 seconds
  • => Jabril's time to reach school: 1800 seconds

<u>Finding the distance of Vaimiti:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • => 1.1 meters/second = Distance/1500
  • => 1.1 x 1500 = Distance
  • => 1650 meters = Distance (In meters)

<u>Finding the distance of Jabril:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • 1.3 meters/second = Distance (In meters)/1800 seconds
  • => 1.3 x 1800 = Distance (In meters)
  • => 2340 meters = Distance (In meters)

This can lead to two possible solutions:

Possible solution #1:

<u>Finding the difference between the two distances:</u>

  • 2340 meters - 1650 meters = Difference (In meters)
  • => 690 meters

Possible solution #2:

The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.

Hoped this helped!

6 0
3 years ago
Read 2 more answers
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