All categories

4 years ago

The kinetic molecular theory predicts that the pressure rises as the temperature of a gas increases because:

Physics

1 answer:

zlopas [31]4 years ago

3 0

The correct answer is

e. both c and d above are true.

In fact, the kinetic molecular theory predicts that when the temperature of a gas increases, the speed of the molecules increases. This means that the particles are more energetic and move faster, and there are two consequences of this:

1) Since the molecules move faster, they collide more frequently with the walls of the container (option c)

2) Since the molecules are more energetic, they collide more energetically with the walls of the container (option d)

As a result, the pressure of the gas increases. So, both options c and d are correct.

You might be interested in

A surface receiving sound is moved from its original position to a position three times farther away from the source of the soun

murzikaleks [220]

As long as all the waves stay in the same medium, the intensity of
any waves ... electromagnetic or mechanical ... decrease in proportion
to the square of the distance.

If the distance increases to 3 x the original distance, then the intensity
changes to 1/3² or 1/9 of the original intensity.

I suppose choice-'d' is the correct one, but I have to tell you that
the phrase "nine times as low" is mathematically meaningless,
and it really grinds my gears.

5 0

3 years ago

Read 2 more answers

The distance between the earth and the sun is about 2.5x10¹¹m. Express SI prefix in kilometers

White raven [17]

Answer: 2.5x10^8 kilometers

Explanation:

Given that:

Distance between the earth and the sun = 2.5x10¹¹metres

Convert distance in metres to kilometers

Recall that 1000 metres = 1 kilometers

So, 2.5x10¹¹metres = Z kilometers

To get the value of Z, cross multiply

Z km x 1000 m = (2.5x10¹¹metres x 1km)

1000Z = 2.5 x 10^11

Divide both sides by Z

1000Z/1000 = 2.5 x 10^11/1000

Z = 2.5x10^8km

Thus, the distance between the earth and the sun is about 2.5x10^8km

6 0

3 years ago

A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.

arlik [135]

Answer:

part (a) v = 1.7 m/s towards right direction

part (b) Not an elastic collision

part (c) F = -228.6 N towards left.

Explanation:

Given,

Mass of the first puck = $m_1\ =\ 5\ kg$
Mass of the second puck = $m_2\ =\ 3\ kg$
initial velocity of the first puck = $u_1\ =\ 3\ m/s.$
Initial velocity of the second puck = $u_2\ =\ -1.5\ m/s.$

Part (a)

Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.

From the conservation of linear momentum,

$m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1u_1\ +\ m_2u_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5}{5\ +\ 1.5}\\\Rightarrow v\ =\ 1.7\ m/s.$

Direction of the velocity is towards right due to positive velocity.

part (b)

Given,

Final velocity of the second puck = $v_2\ =\ 2.31\ m/s.$

Let $v_1$ be the final velocity of first puck after the collision.

From the conservation of linear momentum,

$m_1u_1\ +\ m_2u_2\ +\ m_1v_1\ +\ m_2v_2\\\Rightarrow v_1\ =\ \dfrac{m_1u_1\ +\ m_2u_2\ -\ m_2v_2}{m_1}\\\Rightarrow v_1\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5\ -\ 1.5\times 2.31}{5}\\\Rightarrow v_1\ =\ 1.857\ m/s.$

For elastic collision, the coefficient of restitution should be 1.

From the equation of the restitution,

$v_1\ -\ v_2\ =\ e(u_2\ -\ u_1)\\\Rightarrow e\ =\ \dfrac{v_1\ -\ v_2}{u_2\ -\ u_1}\\\Rightarrow e\ =\ \dfrac{1.857\ -\ 2.31}{-1.5\ -\ 3}\\\Rightarrow e\ =\ 0.1\\$

Therefore the collision is not elastic collision.

part (c)

Given,

Time of impact = t = $25\times 10^{-3}\ sec$

we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

$\therefore I\ =\ \ m_1v_1\ -\ m_1u_1\\\Rightarrow F\times t\ =\ m_1(v_1\ -\ u_1)\\\Rightarrow F\ =\ \dfrac{m_1(v_1\ -\ u_1)}{t}\\\Rightarrow F\ =\ \dfrac{5\times (1.857\ -\ 3)}{25\times 10^{-3}}\\\Rightarrow F\ =\ -228.6\ N$

Negative sign indicates that the force is towards in the left side of the movement of the first puck.

3 0

3 years ago

Which of the following statements about Boyle's law are correct? The temperature and pressure must remain constant for the law t

kvasek [131]

Answer: The temperature and the number of molecules must reamain constant for the law to apply, and as the pressure increases, the volumen decreases proportionally.

Boyle's law states that if the temperature, T, of a given mass of gas, remains constant, the Volume, V, of the gas is in inverse relation to the pressure, p; i.e.

pV = constant (for a given mass of gas, at constant T)

Then, if p increases, V decreases proportionally to keep the relation pV = constant.

8 0

3 years ago

Read 2 more answers

If a 50kg boulder is 100m off the ground and a 25 kg boulder is 100 m off the ground, which has a

Flauer [41]

Answer:

Explanation:

It 100 kg It think

6 0

3 years ago