Given that,
Mass of a baseball, m = 0.2 kg
Initial speed of a baseball, u = 30 m/s
Force produced by a bat, F = 2000 N
Final speed of a baseball, v = -50 (negative for opposite direction)
To find,
For how long was the ball in contact with the bat?
Solution,
Let for t seconds the ball is in contact with the bat. The net force acting on the ball is given by :
So, the ball is contact with the bat for 8 ms.
Answer:
1 and 3
Explanation:
At the point of hitting the tennis ball by the racquet, the force by the hit is acting on the ball.
Since there is a strong wind, the force exerted by the air will act on the tennis ball as it journeys to the ground in the opponents court.
Also, since the tennis ball undergoes a downward motion before it touches the ground, a downward force of gravity also acts on the ball.
After the tennis ball has left contact with the racquet, the force by the hit ceases to act on the ball since they are no longer in contact. However, <em>the downward force of gravity and the force exerted by the air still act on the tennis ball before it touches the ground. </em>
Therefore, the correct choice is:
1 and 3
Answer:
+2m/s
Explanation:
average velocity = displacement traveled / total time taken
= +12m/ 6s
= +2 m/s
The problem was too big to type in my phone.
I hope my answer is readable.
P.S After the collision P is also moving in the same direction as Q.