3.5 is the IQR of <span>0,1,1,3,3,3,4,5, and 7</span>
Answer:
(4,0)
Step-by-step explanation:
(5,3) (1,3)
You need to subtract from the x axis on both coordinates and the y axis in both coordinates.
(5-1) (3-3)
(4,0)
I also checked on a graph as well, so it's correct.
Solution:
1) Rewrite it in the form {a}^{2}-2ab+{b}^{2}, where a={d}^{2} and b=4
{({d}^{2})}^{2}-2({d}^{2})(4)+{4}^{2}
2) Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}
{({d}^{2}-4)}^{2}
3) Rewrite {d}^{2}-4 in the form {a}^{2}-{b}^{2} , where a=d and b=2
{({d}^{2}-{2}^{2})}^{2}
4) Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)
{((d+2)(d-2))}^{2}
5) Use Multiplication Distributive Property: {(xy)}^{a}={x}^{a}{y}^{a}
{(d+2)}^{2}{(d-2)}^{2}
Done!
Answer:
A= -17
Step-by-step explanation:
A +-21 = -38
+21 +21
-38+21= -17
A= -17
1. The slope is -2/5 not 3-/10
