Probability that first student prefers mechanical pen = 0.30
P(first student does not and second student does) = 0.70 * 0.3 = 0.21)
P( selecting 2 or fweer) = 0.30+ 0.21) = 0.51 or 51%
<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
Answer:
<h2>(f•g)(10) = 37</h2><h2 />
Step-by-step explanation:
(f•g)(x) = (x - 4)² + 1
then
(f•g)(10) = (10 - 4)² + 1 = 6² + 1 = 37
Answer:
54 cm
Step-by-step explanation:
Perimeter = TZ + TX + RX + RY + SY + SZ
TZ = 5 cm
TX = 13 cm
RY = 9 cm
RX = TX = 13 cm (tangents drawn from and external point)
SY = RY = 9 cm (tangents drawn from and external point)
SZ = TZ = 5 cm (tangents drawn from and external point)
Plug in the values:
Perimeter = 5 + 13 + 13 + 9 + 9 + 5 = 54 cm
