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3 years ago

Which plate is covering most of two continents ? what two continents?

Physics

2 answers:

Daniel [21]3 years ago

7 0

The Eurasian plate covers most of the continents of Europe and Asia.

ololo11 [35]3 years ago

3 0

The plate that is covering most of the two continents is the Eurasian plate.
The continents are 
1. Europe 
2. Asia
The Eurasian plate is a tectonic plate that amasses the whole continent of what others call as “Eruasia”. It takes part of the oceanic crust that starts from the Mid-Atlantic Ridge and extends itself to northward of the Gakkel Ridge. The size of this plate is for about 67,800,000 km according to statistics and geography.

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Which fact was most likely discovered between the time of Mendeleev’s table and the time of Moseley’s table that helped Moseley

igomit [66]

Answer:

The number of protons in an atom is different than the atom's total mass.

Explanation:

Mendeleev had presented the first structured periodic table in 1869. But, in 1913, Henry Moseley developed the modern periodic table. The crucial difference between the two periodic tables is that Mendeleev's periodic table is generated on the basis of the atomic masses of chemical elements while the chemical element's atomic numbers were the main focus of Moseley's periodic table. There were just 56 chemical elements in Mendeleev's periodic table. On the other hand, 74 chemical elements are presented in Moseley's periodic table.

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3 years ago

If two proton approach each other with speed of 400m\s and 450m\s respectively what is the total momentum of the two particle sy

lilavasa [31]

Answer: $83.65\times 10^{-27}\ kg.m/s$

Explanation:

Given

The velocities of the protons are 400 m/s and 450 m/s

Mass of the Proton is $m=1.673\times 10^{-27}\ kg$

Since they travel in the opposite direction, therefore, their momentum cancels out each other.

Momentum is the product of mass and velocity

$\therefore m(450-400)\\\Rightarrow 1.673\times 10^{-27}\times 50\\\Rightarrow 83.65\times 10^{-27}\ kg.m/s$

The direction of momentum is in the direction of proton having 450 m/s velocity.

7 0

3 years ago

A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds

igomit [66]

The total distance traveled by the body is the sum of the distance it traveled for the first five seconds which is 10 m and that of the next five seconds which is 30 meters. Thus, the total distance traveled is 40 m. Dividing this by the time, will give the average speed. The average speed is therefore, 4 m/s. The answer is letter C.

8 0

3 years ago

Read 2 more answers

A 310-N child is in a swing that is attached to a pair of ropes 2.10 m long. Find the gravitational potential energy of the chil

Softa [21]

Explanation:

Given that,

Force acting on the child, F = 310 N

Length of the ropes, d = 2.1 m

We need to find the gravitational potential energy of the child–Earth system relative to the child's lowest position when the ropes are horizontal. The potential energy is simply given by :

$E=(mg)\times d\\\\E=F\times d\\\\E=310\ N\times 2.1\ m\\\\E=651\ J$

Hence, this is the required solution.

7 0

3 years ago

A box of mass 72 kg is at rest on a horizontal frictionless surface. A constant horizontal force F then acts on the box and acce

zvonat [6]

Answer:

$162\ N$

Explanation:

$We\ are\ given\ that,\\Mass\ of\ the\ box=72\ kg\\Distance/Displacement\ travelled\ by\ the\ box\ during\ the\ application\ of\\ Force=13\ m\\Time\ taken\ for\ it\ to\ displace=3.4 \seconds\\Now,\\As\ we\ know\ that,\\Force=Mass*Acceleration\\In\ order\ to\ know\ force\ we\ need\ to\ know\ the\ acceleration.\ Lets\ find\\ that\ out.\\We\ would\ use\ Newton's\ Third\ Equation\ Of\ Motion\ and\ Newton's\\ First\ Equation\ Of\ Motion:\\2as=v^2-u^2\\v=u+at$

$Hence,\\First\ lets\ consider\ Newtons\ First\ Equation\ Of\ Motion:\\v=u+at\\v-u=at\\Hence\ now\ lets\ move\ on\ to\ Newton's\ Third\ Law\ Of\ Motion:\\2as=v^2-u^2\\2as=(v+u)(v-u)\\Substituting\ (v-u)=at,\\2as=at(v+u) \\Hence,\ as\ the\ body\ moves\ from\ rest,\ u=0\\So,\\2as=at*v\\Cancelling\ a\ at\ both\ the\ sides\ we\ get,\\2s=vt\\Hence,\\Lets\ plug\ in\ the\ values\ of\ Displacement\ and\ Time,\ Shall\ we?\\Hence,\\2*13=3.4v\\26=3.4v\\\frac{26}{3.4}=v\\v \approx 7.647\ m/s$

$Now,\\As\ we\ know\ that,\\a=\frac{v-u}{t} [Equation\ for\ acceleration]\\Hence,\\a=\frac{v}{t} [As\ u=0]\\Hence,\\Acceleration=\frac{7.647}{3.4} \\Acceleration \approx 2.25\ m/s^2\\$

$Hence,\\Now,\\As\ by\ using\ expression\ for\ Force,\\Force= Mass*Acceleration\\Here,\\Force\ exerted\ on\ the\ box=72*2.25= 162 N$

3 0

3 years ago