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Bas_tet [7]
3 years ago
10

You can obtain a rough estimate of the size of a molecule by the following simple experiment. Let a droplet of oil spread out on

a smooth water surface. The resulting oil slick will be approximately one molecule thick. Given an oil droplet of mass of 7.61 × 10−7 kg and density of 912 kg/m3 that spreads out into a circle of radius 43.5 cm on the water surface, estimate the diameter of an oil molecule. Answer in units of m. Your answer must
Physics
1 answer:
Marat540 [252]3 years ago
6 0

Answer:

  • The diameter of the molecule of oil is 1.405 10 ^{-9} \ m

Explanation:

We define density as

\rho = \frac{mass}{volume}

So, the volume for our oil will be

volume = \frac{mass}{\rho}

volume = \frac{7.62 \ 10^{-7} \ kg}{ 912 \ \frac{kg}{m^3}  }

volume = \frac{7.62 \ 10^{-7} \ kg}{ 912 \ \frac{kg}{m^3}  }

volume = 8.355 \ 10 ^{-10} \ m^3

the volume for a cylinder with radius r and height h is

volume = \pi r^2 h

So, we can obtain the height of the droplet of oil as:

h = \frac{volume}{\pi r^2}

the radius is

r=43.5  \ cm = 0.435 \ m

h = 1.405 10 ^{-9} \ m^3

And this is the diameter of the oil molecule.

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zysi [14]

Answer:

internet of things.

Explanation:

The mention Smart refrigerator with information communication system to both manufacturer as well as the customer is an example of internet of things.

The interconnection via internet of computing devices embedded in everyday objects, enabling them to send and receive data. It is also the ability to transfer data without human to human or computer to human interaction.

6 0
3 years ago
How can we produce energy by turning a turbine?​
maw [93]
Wind turbines work on a simple principle: instead of using electricity to make wind—like a fan—wind turbines use wind to make electricity. Wind turns the propeller-like blades of a turbine around a rotor, which spins a generator, which creates electricity.
7 0
3 years ago
How much power does it take to do 500 J of work in 10 seconds?
Dmitry_Shevchenko [17]
Power = work/time
  
          = 500/10
 
          = 50J/s or 50 watt 


7 0
3 years ago
Calculate the acceleration of a 1000 kg car if the motor provides a small thrust of 1000 N and the static and dynamic friction c
grin007 [14]

Explanation :

It is given that,

Mass of the car, m = 1000 kg              

Force applied by the motor, F_A=1000\ N

The static and dynamic friction coefficient is, \mu=0.5

Let a is the acceleration of the car. Since, the car is in motion, the coefficient of sliding friction can be used. At equilibrium,

F_A-\mu mg=ma

\dfrac{F_A-\mu mg}{m}=a

a=\dfrac{1000-0.5(1000)(9.81)}{1000}

a=-3.905\ m/s^2

So, the acceleration of the car is -3.905\ m/s^2. Hence, this is the required solution.

6 0
3 years ago
Two loudspeakers are 1.60 m apart. A person stands 3.00 m from one speaker and 3.50 m from the other. (a) What is the lowest fre
VMariaS [17]

Answer:

Explanation:

Given

Distance between two loud speakers d=1.6\ m

Distance of person from one speaker x_1=3\ m

Distance of person from second speaker x_2=3.5\ m

Path difference between the waves is given by

x_2-x_1=(2m+1)\cdot \frac{\lambda }{2}

for destructive interference m=0 I.e.

x_2-x_1=\frac{\lambda }{2}

3.5-3=\frac{\lambda }{2}

\lambda =0.5\times 2

\lambda =1\ m

frequency is given by

f=\frac{v}{\lambda }

where v=velocity\ of\ sound\ (v=343\ m/s)

f=\frac{343}{1}=343\ Hz

For next frequency which will cause destructive interference is

i.e. m=1 and m=2

3.5-3=\frac{2\cdot 1+1}{2}\cdot \lambda

\lambda =\frac{1}{3}\ m

frequency corresponding to this is

f_2=\frac{343}{\frac{1}{3}}=1029\ Hz

for m=2

3.5-3=\frac{5}{2}\cdot \lambda

\lambda =\frac{1}{5}\ m

Frequency corresponding to this wavelength

f_3=\frac{343}{\frac{1}{5}}

f_3=1715\ Hz                        

8 0
3 years ago
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