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Bas_tet [7]
3 years ago
10

You can obtain a rough estimate of the size of a molecule by the following simple experiment. Let a droplet of oil spread out on

a smooth water surface. The resulting oil slick will be approximately one molecule thick. Given an oil droplet of mass of 7.61 × 10−7 kg and density of 912 kg/m3 that spreads out into a circle of radius 43.5 cm on the water surface, estimate the diameter of an oil molecule. Answer in units of m. Your answer must
Physics
1 answer:
Marat540 [252]3 years ago
6 0

Answer:

  • The diameter of the molecule of oil is 1.405 10 ^{-9} \ m

Explanation:

We define density as

\rho = \frac{mass}{volume}

So, the volume for our oil will be

volume = \frac{mass}{\rho}

volume = \frac{7.62 \ 10^{-7} \ kg}{ 912 \ \frac{kg}{m^3}  }

volume = \frac{7.62 \ 10^{-7} \ kg}{ 912 \ \frac{kg}{m^3}  }

volume = 8.355 \ 10 ^{-10} \ m^3

the volume for a cylinder with radius r and height h is

volume = \pi r^2 h

So, we can obtain the height of the droplet of oil as:

h = \frac{volume}{\pi r^2}

the radius is

r=43.5  \ cm = 0.435 \ m

h = 1.405 10 ^{-9} \ m^3

And this is the diameter of the oil molecule.

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1) +2.19\mu C

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