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mr_godi [17]
3 years ago
7

3

Mathematics
1 answer:
Pani-rosa [81]3 years ago
3 0

Answer:

i thinks it's b

Step-by-step explanation:

I do not no tho

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Linear equations
saw5 [17]

Answer:

Ethan started of with 246,000 Twitter followers

Step-by-step explanation: 12,000 x 4 = 48,000

48,000 + 198,000 = 246,000


3 0
3 years ago
Three scholars each brought bags of skittles at the store that had exactly the same amount in each. Genesis ate 3/6 of a bag of
vlada-n [284]

Answer:

7/6

Step-by-step explanation:

add all numerators together

8 0
4 years ago
(1) a) 5270 cl= ? dal
Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl.

2) When it comes to area, the "ladder scheme" remains valid but now we'll multiply or divide by

10^3

Bear in mind these useful relations:

1litre =\frac{1}{10^3}m^{3}

1 cm^{3} =1 ml

a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}

6 0
3 years ago
A mix of factoring by grouping. Factor the exressions. 17ax+17a-x-1 Please explain/show steps on how to do this!
mario62 [17]

Answer:

(x+1)(17a-1)

Step-by-step explanation:

We are given that

17ax+17a-x-1

We have to factorize the given expression.

Pair up the terms

(17ax+17a)+(-x-1)

Now, taking common factor

17a(x+1)-1(x+1)

Taking common (x+1)

(x+1)(17a-1)

Now, we get

(x+1)(17a-1)

This is required factors of given expression.

4 0
3 years ago
The equation for decibels and sound intensity is D=10log(sub 10) I/I(sub0) where D is decibels.
velikii [3]
D=10\log\dfrac{I}{I_0}\\\\
D=10\log\dfrac{10^{11}}{10^{-12}}\\
D=10\log10^{23}\\
D=10\cdot23=\\
D=230
6 0
3 years ago
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