The system of the linear systems of equation using substitution is;
- x = 2, y = 2
- x = -20, y = -1
<h3>Linear equation</h3>
3x-y=4
x+2y=6
from (2)
x = 6 - 2y
substitute into (1)
3x-y=4
3(6 - 2y) - y = 4
18 - 6y - y = 4
- 6y - y = 4 - 18
-7y = -14
y = 2
Substitute into
x+2y=6
x + 2(2) = 6
x + 4 = 6
x = 6 - 4
x = 2
2. 2x-y= -39
x+y= -21
From (2)
x = -21 - y
substitute into
2x-y= -39
2(-21 - y) - y = -39
-42 - 2y - y = -39
- 2y - y = -39 + 42
- 3y = 3
y = 3/-3
y = -1
substitute into
x+y= -21
x + (-1) = -21
x - 1 = -21
x = -21 + 1
x = -20
3. 2x+y =11
6x-5y =9
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So it will be y1-y2, so 15-20 is -5
Then x1-x2, so 10-15 is -5.
-5/-5 = 1
There’s ya slope : 1
It should be to the right by 2 and up by 2 i’m not to sure tho :/
Answer:
- 750 mL of 0.23% solution
- 250 mL of 0.03% solution
Step-by-step explanation:
Let x represent the quantity (in liters) of the higher percentage solution, the 0.23% solution. Then 1-x will be the quantity of 0.03% solution. The amount of salt in the mix is ...
0.23%·x +0.03%·(1 -x) = 0.18%·1
Multiply by 100% and subtract 3:
20x = 15
x = 15/20 = 0.75 . . . . liters of 0.23% solution
1-x = 1-0.75 = 0.25 . . liters of 0.03% solution
The lab tech needs 750 mL of 0.23% solution and 250 mL of 0.03% solution.
