What is the simplified form of x+6 over x+4 + x-3 over 3
1 answer:
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Answer:
1. Trapezoid
2. Kite
3. Square, Rhombus
Step-by-step explanation:
Given - Use the properties of quadrilaterals to complete the statements.
To find - A ..... has exactly one pair of parallel sides.
A ....... must have two pairs of adjacent sides congruent.
A ........ must have all congruent sides.
Proof -
A Trapezoid has exactly one pair of parallel sides.
A Kite must have two pairs of adjacent sides congruent.
A Square, Rhombus must have all congruent sides.
Reason -
- A trapezoid is a quadrilateral with exactly one pair of parallel sides.
- A kite is a quadrilateral with exactly two pairs of adjacent congruent sides.
- A rhombus is a parallelogram with four congruent sides.
- A square can be defined as a rhombus which is also a rectangle . In other words, a square is a parallelogram with four congruent sides and four right angles.
Answer: p = 0.9337
Step-by-step explanation: from the question, we have that
total number of pen (n)= 15
number of pen that has never been used=9
number of pen that has been used = 15 - 9 =6
number of pen choosing on monday = 3
total number of pen choosing on tuesday=3
note that the total number of pen is constant (15) since he returned the pen back .
probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
probability of picking a pen that has been used on tuesday = 6/15 = 2/5
probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5
on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .
we know that
probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.
to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution
p(x=r) =
n= total number of pens=15
r = number of pen chosen on tuesday = 3
p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5
q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5
by slotting in the parameters, we have that
p(x=3) =
p(x=3) = 455 *
p(x=3) = 455 * 0.064 * 0.002176
p(x=3) = 0.0633
thus probability that 3 of the pens has been used on tuesday. = 0.0633
probability of ball that none of the 3 pen has never being used on tuesday = 1 - 0.0633 = 0.9337