Answer:
We conclude that the total amount accrued, principal plus interest, from compound interest on an original principal of $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.
Step-by-step explanation:
Given
Principle P = $2500
Interest rate r = 5% = 0.05
Time period t = 8 years
To determine
Accrue Amount A = ?
Using the compound interest equation

where:
A represents the Accrue Amount
P represents the Principal Amount
r represents the interest rate
t represents the time period in years
n represents the number of compounding periods per unit t
Important tip:
- Given that the interest is compounded 6 times each year, therefore, the value of n = 6.
now substituting P = 2500, r = 0.05, t = 8 and n = 6 in the equation



∵ 
$
Therefore, we conclude that the total amount accrued, principal plus interest, from compound interest on an original principal of $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.
The function of the water balloon is an illustration of a quadratic function.
The balloon will splat on the ground after 2.5 seconds
The function is given as:

When the balloon splats on the ground, the value of h(t) is 0.
So, we have:

Expand the expression

Factorize the above expression

Factor out 2t - 5 in the 2t - 5

Split the equation into 2

Rewrite as:

Solve for t

The value of t cannot be less than 0 i.e. negative.
So, we have

Divide 5 by 2

Hence, the balloon will splat on the ground after 2.5 seconds
Read more about quadratic functions at:
brainly.com/question/11631534
Answer:
B)1.1
Step-by-step explanation:
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