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3 years ago

Which of the following expressions can be factored by grouping? (Select all that apply.)

Mathematics

1 answer:

Greeley [361]3 years ago

3 0

Answer:

Options (3), (4) and (5)

Step-by-step explanation:

1). a² - 9a + 7ab + 63b

= a(a - 9) + 7b(a + 9)

Now we can not solve this problem further.

Therefore, can't be factored by grouping.

2). 3a + 4ab - b - 12

= a(3 + 4b) - 1(b - 12)

We can't solve it further.

Therefore, can't be factored by grouping.

3). ab + 6b - 2a - 12

= b(a + 6) - 2(a + 6)

= (b - 2)(a + 6)

We can be factored this expression by grouping.

4). x³ + 9x²+ 7x + 63

= x²(x + 9) + 7(x + 9)

= (x² + 7)(x + 9)

Therefore, the given expression can be factored by grouping.

5). ay² + a - y² - 1

= a(y² + 1) - 1(y² + 1)

= (a - 1)(y² + 1)

This expression can be factored by the grouping method.

Options (3), (4) and (5) are the correct answers.

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2 years ago

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Compare your response to the sample response above. what did your explanation include? the conclusion that the work was incorrec

Alenkasestr [34]

In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.

<h3>What is the variables about?</h3>

Note that:

y=-8x+4

y-4=-8x

(y-4)/-8=x

Since the independent variable x is known, one can switch the variable labels and thus it will be:

y=(x-4)/-8

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This can be written again as:

f^-1(x)=(4-x)/8 :P

Thus one can say No, as he forgot to switch the variable labels after solving for the independent variable.

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See the first part of the question below

Talib is trying to find the inverse of the function to the right. His work appears beneath it. Is his work correct? Explain your answer.

Learn more about variable from

brainly.com/question/4063302

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2 years ago

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Firdavs [7]

Answer: <em>23.7</em>

Step-by-step explanation:

<em>Let's calculate the acute angle at the base of the triangle:</em>

$\dfrac{sin \: 90^{o} }{31} =\dfrac{sin \: 50^{o} }{x}\\\\sin \: 90^{o} \cdot x=sin \: 50^{o} \cdot 31\\\\sin \: 90^{o} =1\\sin \: 50^{o} \approx 0.766\\1 \cdot x =0.766 \cdot 31\\x=23.746\\23.746 \approx 23.7$

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