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timurjin [86]
3 years ago
7

Find the 21st term of the arithmetic sequence with a first term

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0
At this case it could be calculated like this: 7+5*20=107
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What is 0.2 as a fraction
Vikentia [17]
It’s 2/10 there you go since there’s no 0 infort of the 2 it’s always a 10
3 0
3 years ago
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i’m so desperate for help i have so many missing assignments and i’m so stressed please just help me get this done
kaheart [24]
It would be J. This is because the opposite of -3.5 would be 3.5 and the absolute value is just a positive integer or positive number so that would be 3.5 as well so its J
7 0
3 years ago
On Friday Merinda uses 1/4 of the box of pancake mix to make pancakes. On Saturday she uses 1 1/2 times as much pancake mix as F
Mashutka [201]

Answer:

3/8 of the box

Step-by-step explanation:

On Friday Merinda uses 1/4 of the box of pancake mix to make pancakes.

On Saturday she uses 1 1/2 times as much pancake mix as Friday.

On Friday = 1/4 of the box

On Saturday = 1 1/2 × pancake mix as Friday

\dfrac{3}{2}\times \dfrac{1}{4}\\\\=\dfrac{3}{8}

Hence, 3/8 of the box of pancake mix does Merinda use on Saturday.

4 0
3 years ago
Adiya said that the first step to solving the quadratic equation x2 + 6 = 20x by completing the square was to divide 6 by 2, squ
Anit [1.1K]
No, actually the method is not correct. Adiya needed to take x2 and subtract it from 20x. she would then get 6 = 18x. Have in mind also that she needed to divide 18. So 6 = 18x turns into 6=X. That is why is incorrect
7 0
3 years ago
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A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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