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timurjin [86]
3 years ago
7

Find the 21st term of the arithmetic sequence with a first term

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0
At this case it could be calculated like this: 7+5*20=107
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Given f(x) = -x – 5, solve for a when f(x) = 4.
Gnoma [55]

Answer:

1

Step-by-step explanation:

plug 4 into x making -4-5 then solve it and it comes out as 1

6 0
3 years ago
The rule that best supports your answer to Question 5 would be:
mixas84 [53]
Sense the two triangles are congruent you would use CPCTC.
6 0
3 years ago
4. Which expression is a simplified form of -5(8x)?<br> a. 40x<br> b. -40%<br> C. 3x<br> d. -40x?
Sedbober [7]

Answer:

Option d

Step-by-step explanation:

-5(8x)

= -5×8×x

= -40x

Answered by GAUTHMATH

5 0
2 years ago
PLEASE HELP due in a few hours!!
notka56 [123]

Answer:

75 meters²

Step-by-step explanation:

4 cm= 5 m

12 cm= 15 m

15×5=75

Area of Patio=75 m²

3 0
3 years ago
In the figure, and bisect each other. Complete the statements to prove that quadrilateral ABCD is a parallelogram.
Alisiya [41]

Observe the figure below.

    Statement                                                                          Reason

1. AC and BD bisect each other                                             Given

2. AE = EC and BE = ED                                                         Definition of bisection

3. m \angle AEB = m \angle CED                       Vertical angle theorem

Vertical angle theorem states " When two lines intersect each other, the vertically opposite angles are always equal".

4. \Delta ABE \cong \Delta CDE                         SAS criterion for congruence

5. m \angle ACD = m \angle CAB           Corresponding angles of congruent triangles are congruent

6. AB \parallel CD                                 Converse of alternate interior angle theorem

7.  m \angle BEC = m \angle AED                   Vertical angle theorem

8.  \Delta BEC \cong \Delta DEA            SAS criterion for congruence

9.  BC \parallel AD                                 Converse of alternate interior angle theorem

As, \Delta BEC \cong \Delta DEA, so m \angle CBD = m \angle BDA as corresponding parts of corresponding triangles are equal. As these angles are alternate interior angles, so the lines BC and AD are parallel by  "Converse of alternate interior angle theorem".

5 0
3 years ago
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