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Sliva [168]
3 years ago
5

Use the system of equations to answer the questions.

Mathematics
1 answer:
koban [17]3 years ago
5 0

Answer:

2x + 3(8 - 3x) = 3

x = 3

y = -1

Step-by-step explanation:

2x + 3y = 3

y = 8 – 3x

2x + 3(8 - 3x) = 3

2x + 24 - 9x = 3

7x = 21

x = 3

y = 8 - 3(3)

y = -1

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posledela

The statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

<h3>How to determine which statement is true?</h3>

To determine which statement is true, we need to know the conditions for continuity and differentiablity of a function.

<h3>Conditions for continuity and differentiablity of a function.</h3>
  • For a function f(x) to be continuous at a point x = a, then both the left hand limit of f(x) and the right hand limit of f(x) as x → a must be equal. That is \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x). So,  \lim_{x \to a^{} } f(x) must exist since  \lim_{x \to a^{-} } f(x) =  \lim_{x \to a^{+} } f(x) =  \lim_{x \to a^{} } f(x)
  • Also, for a function to be differentiable at a point x = a, it must also exist at x = a

So, since f(x) = {x² - 1 if -1 ≤ x ≤ 3 and x²/3 if 3 < x ≤ 8}

From the equality on the first condition,we see that f(x) is exists at x = 3 but is not continuous since f(x) changes to another function when x > 3. So,left hand limit of f(x) and the right hand limit of f(x) as x → 3 are not equal.

That is \lim_{x \to 3^{-} } f(x) \neq   \lim_{x \to 3^{+} } f(x) . Thus, the function is discontinuous at x = 3.

For differentiability, both conditions must be met. Since only one condition is met, it is non-differentiable.

So, the function is discontinuous and non-differentiable at x = 3.

So, the statement that is true about the function is D. it is discontinuous and non-differentiable at x = 3.

Learn more about continuity of a function here:

brainly.com/question/24177259

#SPJ1

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2 years ago
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