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makkiz [27]
3 years ago
15

Sam scored 80% on Part A of a math test and 92% on part B of the math test. His total mark on the test was 63. The total possibl

e marks for the test was 75. Which system of equations represents the situation?
Mathematics
1 answer:
Nataly_w [17]3 years ago
6 0

Answer:

0.80A + 0.92B = 63 .....1

A + B = 75 ......2

Step-by-step explanation:

Let A and B represent the total possible score in part A and B respectively;

Analysing each sentence of the question;

Sam scored 80% on Part A of a math test and 92% on part B of the math test. His total mark on the test was 63

80% of A + 92% of B = 63

0.80A + 0.92B = 63 ......1

The total possible marks for the test was 75;

A + B = 75 .....2

So, equation 1 and 2 provides a set of simultaneous equations that can be used to represent and solve the situation.

Solving the simultaneous equations, we will arrive at;

Part A = 50

Part B = 25

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Las llantas de un automóvil pequeño tiene una medida de 14 pulgadas de diámetro.Realiza la gráfica de una de las llantas colocan
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Answer:

Invitamos cordial a revisar la imagen adjunta abajo para mayor detalle sobre la gráfica de las llantas.

La forma general de la circunferencia de la llanta está representada por x^{2}+y^{2}-49 = 0.

Step-by-step explanation:

A continuación, anexamos una representación de las llantas del automóvil como una circunferencia centrada en el origen y con un diámetro de 14 pulgadas, es decir, un radio de 7 pulgadas.

La ecuación estándar de la circunferencia centrada en un punto dado y con un radio determinado está definida por:

(x-h)^{2}+(y-k)^{2} =r^{2} (1)

Donde:

h, k - Coordenadas del centro de la circunferencia, medidas en pulgadas.

r - Radio de la circunferencia, medido en pulgadas.

Si conocemos que h = 0\,in, k = 0\,in y r = 7\,in, entonces la ecuación estándar que representa a la circunferencia de la llanta es:

x^{2}+y^{2} = 49

Ahora, la ecuación general de la circunferencia centrada en el origen satisface la siguiente expresión:

A\cdot x^{2}+A\cdot y^{2}+B = 0 (2)

Donde A, B son los coeficientes de forma de la circunferencia.

Entonces, la forma general de la circunferencia de la llanta está representada por la siguiente expresión:

x^{2}+y^{2}-49 = 0

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3 years ago
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Check the picture below.

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3 years ago
Read 2 more answers
The graph of a sinusoidal function has a minimum point at (0,3)(0,3) and then intersects its midline at (5π,5)
bekas [8.4K]

Answer: F(x) = 2*sin(x/10  +(3/2)*pi) + 5

Step-by-step explanation:

The information that we have is that:

We have a minimum at (0, 3)

the midline is at (5*pi, 5)

This is a sinusoidal function, so we can write one generic one as:

F(x) = A*sin(c*x + p) + B.

where A and B are constants, c is the frequency and p is a phase

First, the minimum of the sine function is when sin(x) = -1, and this happens at (3/2)*pi

We know that this minimum is at x = 0.

sin(c*0 + p) = -1

Then p = 3/2*pi.

So our function is:

F(x) = A*sin(c*x  +(3/2)*pi) + B.

Now, we know that F(0) = 3, so:

3 = A*sin(c*0 +(3/2)*pi) + B = -A + B.

now we can use the other hint, the midpoint of the sine function is when sin(x) = 0, and this happens at x = 0 and x = pi, particularlly as we here have a phase of 3/2*pi, we should find x = 2*pi.

then:

c*5*pi + (3/2)*pi = 2*pi

c*5 + 3/2 = 2

c*5 = 2 - 3/2 = 1/2

C = 1/2*5 = 1/10

So our function is

F(x) = A*sin(x/10  +(3/2)*pi) + B

and we know that when x = 5*pi, F(5*pi) = 5, so:

5 = F(x) = A*sin(5*pi/10  +(3/2)*pi) + B

5 = B

and we aready knew that:

- A + B = 3

-A + 5 = 3

A = 5 - 3 = 2

So our equation is:

F(x) = 2*sin(x/10  +(3/2)*pi) + 5

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A. Y=x+2




I thinks that’s right hope this helps :)
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