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2 years ago

The weight of an astronaut on the moon is the same as on Earth. True False

Physics

2 answers:

Vaselesa [24]2 years ago

5 0

Answer:

False

Explanation:

This is due to the gravitational pull, since the moon does not have the same force or gravity like Earth, your weight would change.

☆anvipatel77☆

•Expert•

Brainly Community Contributor

tangare [24]2 years ago

5 0

False. Looking at the equation g=GM/r^2, the mass of the object creating gravity (the moon) is directly proportional to gravitational field strength. This means that the lower the mass of the object, the weaker the gravitational field strength will be. Since the moon is nowhere near as massive as earth, the gravitational field strength is weaker than it would be on earth, meaning your weight will be different.

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use the instantaneous center of zero velocity to determine the angular velocity !ab of link ab and the velocity vb of collar b f

allsm [11]

Instantaneous center:

It is the center about a body moves in planer motion. The velocity of Instantaneous center is zero and Instantaneous center can be lie out side or inside the body. About this center every particle of a body rotates.

From the diagram

Where these two lines will cut then it will the I-Center.Point A and B is moving perpendicular to the point I.

If we take three link link1,link2 and link3 then I center of these three link will be in one straight line It means that they will be co-linear.

Therefore, when the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.

To know more about velocity, refer: brainly.com/question/12413963

#SPJ4

7 0

1 year ago

A uniform rod rotates in a horizontal plane about a vertical axis through one end. The rod is 3.46 m long, weighs 12.8 N, and ro

Mkey [24]

Answer:

a. Rotational inertia: 5.21kgm²

b. Magnitude of it's angular momentum: 123.32kgm²/s

Explanation:

Length of the rod = 3.46m

Weight of the rod = 12.8 N

Angular velocity of the rod= 226 rev/min

a. Rotational Inertia (I) about its axis

The formula for rotational inertia =

I = (1/12×m×L²) + m × ( L ÷ 2)²

Where L = length of the rod

m = mass of the rod

Mass of the rod is calculated by dividing the weight of the rod with the acceleration due to gravity.

Acceleration due to gravity = 9.81m/s²

Mass of the rod = 12.8N/ 9.81m/s²

Mass of the rod = 1.305kg

Rotational Inertia =

(1/12× 1.305 × 3.46²)+ 1.305 ( 3.46÷2)²

Rotational Inertia = 1.3019115 + 3.9057345

Rotational Inertia = 5.207646kgm²

Approximately = 5.21kgm²

b. The magnitude of the rod's angular momentum about the rotational axis is calculated as

Rotational Inertia about its axis × angular speed of the rod.

Angular speed of the rod is calculated as= (Angular velocity of the rod × 2π)/60

= (226×2π) /60

= 23.67 rad/s

Rotational Inertia = 5.21kgm²

The magnitude of the rod's angular momentum about the rotational axis

= 5.21kgm²× 23.67 rad/s

= 123.3207kgm²/s

Approximately = 123.32kgm²/s

7 0

3 years ago

A 2.45 cm tall object is placed in 33.7 cm in front of a convex lens. The focal length

timofeeve [1]

Answer:

-1.65

Explanation:

First of all, we find the position of the image by using the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where:

f is the focal length of the lens

p is the distance of the object from the lens

q is the distance of the image from the lens

For the lens in this problem:

f = 21.0 cm (the focal length of a convex lens is positive)

p = 33.7 cm

Solving for q, we find the position of the image:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{21.0}-\frac{1}{33.7}=0.0179 cm^{-1}\\q=\frac{1}{0.0179}=55.7 cm$

Then, the magnification of the image is given by:

$M=-\frac{q}{p}$

And substituting,

$M=-\frac{55.7}{33.7}=-1.65$

Which means that the image is inverted (negative sign) and enlarged (because M is larger than 1).

3 0

3 years ago

Although you can see the pencil, it appears broken in the glass of water. This is because

Likurg_2 [28]

Hello,

Although you can see the pencil, it appears broken in the glass of water. This is because <span>electromagnetic waves travel at different speeds through different media.

Mark brainliest if helped!</span>

8 0

3 years ago

Read 2 more answers

The effects of agriculture and industry can be more harmful with the further loss of wetlands.

Anna71 [15]

Yes, it is true that the effects of agriculture and industry can be more harmful with the further loss of wetlands since industry usually requires large amounts of land.

7 0

3 years ago