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2 years ago

The weight of an astronaut on the moon is the same as on Earth. True False

Physics

2 answers:

Vaselesa [24]2 years ago

5 0

Answer:

False

Explanation:

This is due to the gravitational pull, since the moon does not have the same force or gravity like Earth, your weight would change.

☆anvipatel77☆

•Expert•

Brainly Community Contributor

tangare [24]2 years ago

5 0

False. Looking at the equation g=GM/r^2, the mass of the object creating gravity (the moon) is directly proportional to gravitational field strength. This means that the lower the mass of the object, the weaker the gravitational field strength will be. Since the moon is nowhere near as massive as earth, the gravitational field strength is weaker than it would be on earth, meaning your weight will be different.

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Answer:

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Explanation:

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Answer:

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Explanation:

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3 years ago

Read 2 more answers

Estimate the electric field at a point 2.40 cm perpendicular to the midpoint of a uniformly charged 2.00-m-long thin wire carryi

nadya68 [22]

Answer:

$E = 1.85*10^{12}\frac{N}{C}$

Explanation:

Hi!

The perpendicular distance 2.4cm, is much less than the distance to both endpoints of the wire, which is aprox 1m. Then the edge effect is negligible at this field point, and we can aproximate the wire as infinitely long.

The electric filed of an infinitely long wire is easy to calculate. Let's call z the axis along the wire. Because of its simmetry (translational and rotational), the electric field E must point in the radial direction, and it cannot depende on coordinate z. To calculate the field Gauss law is used, as seen in the image, with a cylindrical gaussian surface. The result is:

$E = \frac{\lambda}{2\pi \epsilon_0 r}\\\lambda=\text{charge per unit length}=\frac{4.95 \mu C}{2 m} = 2.475 \frac{C}{m}\\r=\text{perpendicular distance to wire}\\\epsilon_0=8.85*10^{-12}\frac{C^2}{Nm^2}$

Then the electric field at the point of interest is estimated as:

$E = \frac{\22.475}{2\pi*( 8.85*10^{-12})*(2.4*10^{-2})}\frac{N}{C}=1.85*10^{12}\frac{N}{C}$

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3 years ago