Explanation:
the answer is in the above image
A calcium-40 ion has a positive charge that is double the charge of a proton, and a mass of 6.64 ✕ 10−26 kg. At a particular ins
tant, it is moving with a speed of 5.00 ✕ 106 m/s through a magnetic field. At this instant, its velocity makes an angle of 61° with the direction of the magnetic field at the ion's location. The magnitude of the field is 0.230 T.
(a)What is the magnitude of the magnetic force (in N) on the ion?
N
B)What is the magnitude of the ion's acceleration (in m/s2) at this instant?
m/s2
(a)What is the magnitude of the magnetic force (in N) on the ion?
N
B)What is the magnitude of the ion's acceleration (in m/s2) at this instant?
m/s2
1 answer:
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Answer:
Explanation:
Given
mass of bus along with travelers travelling in North direction is
speed of bus towards North
mass of bus travelling in South direction is
speed of bus
mass of each Passenger in south moving bus
Momentum of North moving bus
Momentum with south moving bus
For total momentum to be towards south
should be greater than 0
thus for least value of n