A calcium-40 ion has a positive charge that is double the charge of a proton, and a mass of 6.64 ✕ 10−26 kg. At a particular ins
tant, it is moving with a speed of 5.00 ✕ 106 m/s through a magnetic field. At this instant, its velocity makes an angle of 61° with the direction of the magnetic field at the ion's location. The magnitude of the field is 0.230 T.
(a)What is the magnitude of the magnetic force (in N) on the ion?
N
B)What is the magnitude of the ion's acceleration (in m/s2) at this instant?
m/s2
(a)What is the magnitude of the magnetic force (in N) on the ion?
N
B)What is the magnitude of the ion's acceleration (in m/s2) at this instant?
m/s2
1 answer:
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Explanation:
Suppose the cheetah is initially positioned at x=0 (m) from the reference, and the gazelle is intially at poisiton x=d (m).
Then, at the worst case, that is when cheetah is running at the maximum case, the position of the gazelle relative to the reference must be larger than that of cheetah.
In equation form,
Answer:
69 revolutions
Explanation:
given,
initial angular velocity = 0
final angular velocity = 6 rev/s
when safety switch turned off
tub smoothly slows to rest in (t)= 13 s
total revolution of tub = ?
angular acceleration =
angular acceleration =
= 0.6 rev/s²
now,
= 30 revolution
now,
when safety switch turn off
angular acceleration =
angular acceleration =
= -0.462 rev/s²
now,
= 39 revolution
total revolution = 30 + 39 = 69 revolutions.
tub will rotate 69 revolutions