Answer: Provided in the explanation section
Explanation:
The question to this problem says;
Question:
I am sorting data that is stored over a network connection. Based on the properties of that connection, it is extremely expensive to "swap" two elements. But looping over the elements and looking at their values is very inexpensive. I want to minimize swaps above all other factors. Choose the sorting algorithm we studied that will perform the best:
ANSWER
1. Merge Sort
Because merge sort uses additional memory instead of swapping the elements.
2. Merge Sort and Quick Sort both can be used with multi processor.
cheers i hope this helps !!!
The price could go up, it might not work then later down the road
Answer:
A. Big Data
Explanation:
It is big data. The internet searches, customer transactions, social media posts, medical tests, weather sensors, military surveillance, and all the data source you are seeing around yourself forms together with the big data. And a big social media company gathers around so many petabytes of data each day. And there are so many such companies, plus all sorts like eLearning sites, etc. And all these together form the big data.
Cognitive surplus results when leisure time and available tools allow us to engage in creative acts. It is a term that was introduced by Clay Shirky which pertains to the synthesis of the excess of people's energy, time and creativity leading to productivity sharing and creation.
Answer:
if full_admission_price = f and discount_amount = d
=> Price of a discount admission = d/f
total_weight
quantity
weight of one item = total_weight/quantity
for i in range(80, 18, -2):
print(i, end=' ')
Explanation:
The first two questions are just mathematical to get a single quantity given some relationship. So, its basically division
For the python code, I used the python's range function which takes in three arguments. The first one is the starting value, the second one is the terminating value which is the number before the terminating value and the last one specifies the common difference popularly known as step in the language. Since the step is 2, only even numbers are printed out. In the print function, I made use of the end keyword specifying a space (' ') as the end. This ensures that the print is done in the same line with a space seperating them. Without that specification, each result will printed in a newline
