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Genrish500 [490]
2 years ago
8

The label on a juice carton says there are 50 calories in a 4 ounce serving of juice. If Arthur drinks 12 ounces of juice, how m

any calories will he consume?
A. 200 calories
B. 150 calories
C. 58 calories
D. 48 calories
Mathematics
2 answers:
hodyreva [135]2 years ago
6 0
He will consume 150 calories. I found the unit rate by dividing 50 calories by 4 ounces to get 12.5 calories per 1 ounce. I multiplied 12.5 calories by 12 ounces to get 150 calories.
ValentinkaMS [17]2 years ago
4 0
First we need to do 12 ÷ 4 to see how many times that goes in. You get 3. Then you do
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Four different sets of objects contain 4, 5, 6, and 8 objects, respectively. How many unique combinations can be formed by picki
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You would multiply all of the numbers to get your answer so it would be 4*5*6*8 which would get you 960.

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In a basketball skills competition, Corson successfully made 5 of 7 shots and Charleigh made 3 of 5
xxTIMURxx [149]

Answer:

Corson had a better performance at the skills competition.

Step-by-step explanation:

In order to determine which player had a better performance at the skills competition, we need to find the percentage performance of both the players.

Therefore,

Corson's percentage performance

=\frac{5}{7}\times 100= 71.43%

Charleigh's percentage performance

=\frac{3}{5}\times 100= 60%

\because Corson's percentage performance > Charleigh's percentage performance

So, Corson had a better performance at the skills competition.

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2 years ago
Choose Positive or Negative for each expression.
Anton [14]

Answer:

A. negative

B. positive

C. positive

D. negative

hope this helps!

Step-by-step explanation:

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Paired t‐Test for Mean Comparison with Dependent Samples To study the effects of an advertising campaign at a supply chain, seve
Lapatulllka [165]

Answer:

a) t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.7 -0}{\frac{0.678}{\sqrt{5}}}=2.308  

p_v =P(t_{(4)}>2.308) =0.0411

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

b) The p value is illustrated on the figure attached.

If we select \alpha=0.01 we see that p_v >\alpha so then we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Part a

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

1=test value old , 2 = test value new

1: 5.2 6.5 7.2 5.7 7.6

2: 6.4 7.8 6.8 6.5 8.2

The system of hypothesis for this case are:

Null hypothesis: \mu_2- \mu_1 \leq 0

Alternative hypothesis: \mu_2 -\mu_1 >0

The first step is calculate the difference d_i=y_i-x_i and we obtain this:

d: 1.2, 1.3, -0.4, 0.8, 0.6

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=0.7

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =0.678

The 4 step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.7 -0}{\frac{0.678}{\sqrt{5}}}=2.308

The next step is calculate the degrees of freedom given by:

df=n-1=5-1=4

Now we can calculate the p value, since we have a right tailed test the p value is given by:

p_v =P(t_{(4)}>2.308) =0.0411

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.  

Part b

The p value is illustrated on the figure attached.

If we select \alpha=0.01 we see that p_v >\alpha so then we have enough evidence to FAIL to reject the null hypothesis.

7 0
2 years ago
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