59pounds * 5days = 295pounds
6.95pounds * 3breakfasts = 20.85pounds
12.50pounds * 1eveningmeal = 12.50pounds
295pounds + 20.85pounds + 12.50pounds = 328.35pounds
Wrote out the units just for clarity! Liz payed 328.25 pounds altogether.
Answer:
So, the required width of rectangular piece of aluminium is 8 inches
Step-by-step explanation:
We are given:
Perimeter of rectangular piece of aluminium = 62 inches
Let width of rectangular piece of aluminium = w
and length of rectangular piece of aluminium = w+15
We need to find width i.e value of x
The formula for finding perimeter of rectangle is: 
Now, Putting values in formula for finding Width w:

After solving we get the width of rectangular piece :w = 8
So, the required width of rectangular piece of aluminium is 8 inches
Remember
(ab)/(cd)=(a/c)(b/d)
and

1kg=1000g=1*10^3g
hmm, I estimate, 4 of them
x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=

=

=

a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg
a. 4
b. underestimate
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