The answer would be 50x because the magnification of a specimen viewed with a compound light microscope that has an objective power of 10x and an ocular lens power of 5x is equal to 50x. Magnification is equivalent to the product of the objective power and the ocular lens. Ten times five is fifty.
Answer:
To balance the production of certain products.
Explanation:
Feedback inhibition is when byproduct from metabolic reactions in cells accumulates and is in excess. The product goes and inhibits the enzyme that is responsible for speeding its chemical reaction, balancing the amount of product needed, with the amount already produced.
Therefore feedback inhibition is important in metabolic pathways because it balances the production of amino acids and nucleotides. It is there to ensure that the exact amount needed is produced.
Answer:
Conductors
Explanation: the substances which have a large number of free electrons and offer a low resistance are called conductors
Answer:
Alleles for albinism:
C (dominant)
c (recessive)
Genotypes:
- A: Cc
- B: Cc
- C: Cc
- D: Cc
- E: cc
- F: CC (expected genotype)
- G: CC
Explanation:
In humans, albinism is controlled by a single recessive allele 'c', whereas normal pigmentation of the skin is controlled by the normal allele 'C'. Moreover, a pedigree is a diagram that shows the inheritance pattern of a particular disease/disease through several generations. In a pedigree, a shaded circle (female) or a shaded square (male) indicates that the person expresses the disease/trait. On the other hand, an unfilled circle/square indicates that the person does not have the genetic trait. A carrier (heterozygous) individual can be represented by a half-shaded circle/square. In this pedigree, the genotypes of carrier and non-carriers individuals are represented by unfilled circles or squares; however, these genotypes can be deduced by determining the genotypes of their parents. For example, both A and B don't express the trait but they have a daughter (E individual) with albinism (cc genotype), thereby both A and B individuals need to be carriers (Cc genotype) for the trait.