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aksik [14]
4 years ago
7

The shop declare a discount of 20% and later a discount of 15% after

Mathematics
2 answers:
Musya8 [376]4 years ago
5 0
The shop gave a Total discount 35%
elena55 [62]4 years ago
3 0
Total discount will be 35%.
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Don't know how to express the value of X as any of those answer choices
Alekssandra [29.7K]

9514 1404 393

Answer:

  x = √(w(w+z))

Step-by-step explanation:

The idea with a right-triangle figure of this sort is that all of the triangles are similar. Here, x is the short side of ∆ABC, and the hypotenuse of ∆BDC. This suggests you want to write a similarity statement involving the short side and hypotenuse.

  BC/AC = DC/BC . . . . . short side/hypotenuse

  BC² = AC·DC . . . . . . cross multiply

  x² = (w+z)w . . . . . . substitute letter values

Taking the square root and rearranging to the form of the applicable answer choice, this is ...

  \boxed{x=\sqrt{w(w+z)}}

3 0
3 years ago
P is the point on the line 2x+y-10=0 such that the length of OP, the line segment from the origin O to P, is a minimum. Find the
nirvana33 [79]
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span>                                      =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x 
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2)   (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
 
Then y = 10 - 2(4) = 2.
 So the point, P, is (4,2).
8 0
4 years ago
One light-year equals 5.9 x 1012 miles. How many light-years are in 6.79
inna [77]

Option B

The number of light years in 6.79 \times 10^{16} miles is 11508 light years

<em><u>Solution:</u></em>

Given that,

One light-year equals 5.9 x 10^12 miles

Therefore,

1 \text{ light year } = 5.9 \times 10^{12} \text{ miles }

To find: Number of light years in 6.79 \times 10^{16} miles

Let "x" be the number of light years in 6.79 \times 10^{16} miles

Then number of light years in 6.79 \times 10^{16} miles can be found by dividing 6.79 \times 10^{16} miles by miles in 1 light year

\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79 \times 10^{16}}{5.9 \times 10^{12}}\\\\\text{Use the law of exponent }\\\\\frac{a^m}{a^n} = a^{m-n}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79}{5.9} \times 10^{16-12}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 1.1508 \times 10^4\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 11508

Thus number of light years in 6.79 \times 10^{16} miles is 11508 light years

3 0
3 years ago
High Points!!!
Karo-lina-s [1.5K]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
The vertices of quadrilateral E F G H are E (-7,3) , F (-4,6) , G (5, -3) , and H (2,-6). What kind of quadrilateral is E F G H?
Norma-Jean [14]

Answer:

square

Step-by-step explanation:

The opposite angles are congruent, the diagonals bisect each other, the opposite sides are parallel, the diagonals bisect the angles

7 0
3 years ago
Read 2 more answers
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