Answer:
C. 0.1515
Step-by-step explanation:
The main objective here is to find the P-value for the test of
Given that ;
the mean value = 2.2
the standard deviation = 1.4
number of recorded accident per week = 52
The null hypothesis is :
The alternative hypothesis is :
The Z- value can be calculated as:
z = -1.03
From the normal distribution table for probability;
P(z< -1.03 ) = 0.1515