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Rus_ich [418]
3 years ago
8

I need help on #59, #60

Mathematics
2 answers:
lara [203]3 years ago
8 0
59 3x+10 =5x-90
100=. 2x
50=x
Measure angle 0 is 20
60 2x=3x-20
20=x
Angle 0=140
astra-53 [7]3 years ago
6 0
# 59
3x + 10 = 5x -90 because they are vertical angles and vertical angles are congruent.
Solve for x
3x + 10 = 5x - 90
Subtract 3x from both sides
10 = 2x -90
Add 90 to both sides
100 = 2x
Divide by 2
50 = x
Either of these angles with theta will add to 180.
3(50)+ 10 + theta = 180
160 + theta = 180
Subtract 160
Theta = 20
# 60
Again 3x -20 =2x
Subtracting 3x from both sides
-20 = -x
Divide by -1
x = 20
2(20) + theta = 180
40 + theta = 180
Theta = 140
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We can use the identity:

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sin(x+y) = sin(x) cos(y)+cos(x)sin(y)

sin(180° + 75°) = sin(180°) cos(75°)+cos(180°)sin( 75°)

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Putting values,

sin(180° + 75°) = 0 (√6 -√2/4) + (-1)(√2 + √6/4)

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sin(-255°)  = -(-(√2 + √6/4))

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Read 2 more answers
write the equation in slope intercept form of the line that passes through -1, 11 and is parallel to the graph of y = -8x + 3
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<h2>Answer: The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ). </h2>

<h3 /><h3>Step-by-step explanation: </h3>

<u>Find the slope of the parallel line</u>

When two lines are parallel, they have the same slope.

                 ⇒  if the slope of this line = - 8

                      then the slope of the parallel line (m) = - 8

<u>Determine the equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:  

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                                ∴  y - 11  = - 8 (x + 1)

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

                      since   y - 11  = - 8 (x + 1)

                                        y  = - 8 x  + 3

The line from the question [ y = -8x + 3 ] passes through the point ( -1, 11 ).

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