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statuscvo [17]
4 years ago
11

What is half of the product of 8 1/7 and 7 4/5

Mathematics
1 answer:
UNO [17]4 years ago
6 0

First we must convert these mixed numbers to improper fractions:

8\frac{1}{7}=\frac{57}{7}

7\frac{4}{5}=\frac{39}{5}

So then we need the product of these two numbers. That means to multiply:

\frac{57}{7}* \frac{39}{5}= \frac{2,223}{35}

But then we need the value of half of this product. So then let's multiply by one-half:

\frac{2,223}{35} *\frac{1}{2} =\frac{2,223}{70}

Then we can convert this from an improper fraction to a mixed number:

\frac{2,223}{70} =31\frac{53}{70}

And so this number is half of the product of the initial two numbers.

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Step-by-step explanation:

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<em />

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Step-by-step explanation:

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x = ----------------- = -------------------  and   x = --------------------

            3                         3                                     3

Normally, if c is a root, then x - c is a factor.

If we try this here, however, the resulting factors do not at all match any of your answer choices.

Don't be offended...but please ensure you have copied this problem down correctly.

                                                           

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Step-by-step explanation:

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