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statuscvo [17]
3 years ago
11

What is half of the product of 8 1/7 and 7 4/5

Mathematics
1 answer:
UNO [17]3 years ago
6 0

First we must convert these mixed numbers to improper fractions:

8\frac{1}{7}=\frac{57}{7}

7\frac{4}{5}=\frac{39}{5}

So then we need the product of these two numbers. That means to multiply:

\frac{57}{7}* \frac{39}{5}= \frac{2,223}{35}

But then we need the value of half of this product. So then let's multiply by one-half:

\frac{2,223}{35} *\frac{1}{2} =\frac{2,223}{70}

Then we can convert this from an improper fraction to a mixed number:

\frac{2,223}{70} =31\frac{53}{70}

And so this number is half of the product of the initial two numbers.

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In a triangle, the measure of an angle is in the same order of size as the length of the opposite side. The smallest angle is opposite the shortest side. The largest angle is opposite the longest side. The middle-sized angle is opposite the middle-sized side.

Also, in a triangle, the sum of the measures of the interior angles is 180.

We can now calculate the measures of the three angles by writing and solving an equation.

m<A + m<B + m<C = 180

9x - 7 + 7x - 9 + 28 - 2x = 180

Collect like terms on the left side.

9x + 7x - 2x - 7 - 9 + 28 = 180

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Subtract 12 from both sides.

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Now that we know x, we can find the measure of each angle.

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(Quick check: Add the angles measures: 101 + 75 + 4 = 180. The sum is 180 as it should be.)

Now that we know the angle measures, the opposite sides are in the same order of size.

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The sides are, in increasing order of length:

AB, AC, BC
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