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statuscvo [17]
3 years ago
11

What is half of the product of 8 1/7 and 7 4/5

Mathematics
1 answer:
UNO [17]3 years ago
6 0

First we must convert these mixed numbers to improper fractions:

8\frac{1}{7}=\frac{57}{7}

7\frac{4}{5}=\frac{39}{5}

So then we need the product of these two numbers. That means to multiply:

\frac{57}{7}* \frac{39}{5}= \frac{2,223}{35}

But then we need the value of half of this product. So then let's multiply by one-half:

\frac{2,223}{35} *\frac{1}{2} =\frac{2,223}{70}

Then we can convert this from an improper fraction to a mixed number:

\frac{2,223}{70} =31\frac{53}{70}

And so this number is half of the product of the initial two numbers.

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Which point lies on a circle with a radius of 5 units and center at P(6, 1)?
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Answer:

B.

R (2,4)

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so

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RUDIKE [14]
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9514 1404 393

Answer:

  x = 10

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  x/8 = (x +5)/12

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<em>Alternate solution</em>

We observe that the difference between the upper segment lengths is ...

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3 years ago
(2^8 . 5-5 . 19^-2) . {5^2over2^3} . 2^28 show steps2^28
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Step-by-step explanation:

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