We're provide - Sin θ = $\frac{12}{37}$ which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = $\tt{ \frac{p}{h}}$ ] . We're asked to find out tan θ ].

$\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :$

$\large{ \tt{❊ \: {h}^{2} = {p}^{2} + {b}^{2} }}$

$\large{ \tt{⇢ {p}^{2} + {b}^{2} = {h}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {h}^{2} - {p}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {37}^{2} - {12}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = 1369 - 144}}$

$\large{ \tt{ ⇢{b}^{2} = 1225}}$

$\large{ \tt{⇢ \: b = \sqrt{1225}}}$

$\large{ \tt{⇢ \: b = 35 \: \text {units}}}$

Now , We know - Tan θ= $\tt{ \frac{perpendicular}{base} }$ . Just plug the values :

$\large{ \tt{➝ \: Tan \: \theta = \frac{p}{b} = \boxed{ \tt{ \frac{12}{35} }}}}$

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5 0

3 years ago

Alexxandr [17]

Answer:

Quadrilaterals

Step-by-step explanation:

4 0

3 years ago