What is the altitude of the triangle?
1 answer:
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The volume of <span>a right square pyramid is 
, where </span><span>
is basis area.
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If the lengths of the sides of the base remain fixed and height
<span>is multiplied by a factor 10, than new height is
and the volume is
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If the lengths of the sides of the base remain fixed and height
<span>is multiplied by a factor 10, than new height is
</span>
The length of ED is half the length of AB.
<h3>What is the length?</h3>- Distance is measured by length.
- Length is a quantity with the dimension distance in the International System of Quantities.
- Most measurement systems use a base unit for length from which all other units are derived.
- The meter is the foundation unit of length in the International System of Units.
Reasons:
The given parameters are;
In ΔABC, point E is the midpoint of AC
The midpoint of BC is the point D
Segment ED = s
Segment CE = p
Segment EA = r
Segment CD = q
Segment DB = t
Segment ED = s
Segment AB = u
Required:
The expression that represents the value of .
Solution:
CE = 0.5 × AC Definition of midpoint
CD = 0.5 × CB Definition of midpoint
Therefore, we have;
Therefore, given that ∠C ≅ ∠C, by the reflexive property, we have;
ΔABC is similar to ΔCDE by Side-Angle-Side similarity
Which gives;
ED = s and AB = u which gives;
Which gives:
The expression that represents the value of s is; s = one-half u
Therefore, the length of ED is half the length of AB.
Know more about the length here:
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The question you are looking for is here:
If point E is the midpoint of segment AC and point D is the midpoint of segment BC, which expression represents the value of s? triangle CAB, point E is on segment AC between points A and C and point D is on segment BC between points B and C, creating segment ED, CE equals p, EA equals r, CD equals q, DB equals t, ED equals s, and AB equals u s equals p over q s = one half s equals q over p s = 2u
Answer: 1.48ft
Step-by-step explanation:
The angle, θ, at which the projector "spreads" the image is constant.
We know that:
"A movie projector positioned 34 feet from a wall creates an image that is 8 feet wide on the wall"
We can think this problem as the image in the end, two triangle rectangles with cathetus equal to 34 ft, and 8/2 ft = 4ft
Then this angle θ can be calculated because we know the two cathetus of this triangle:
Tan(θ) = (opposite cathetus)/(adjacent cathetus)
Tan(θ) = 4ft/34ft
θ = Cotan(4/34) = 8.46°
Now, if you move the place the projector 5ft from the wall, now the adjacent cathetus is 5ft instead of 34.
Then we have:
Tan(8.46°) = x/5ft
Tan(8.46°)*5ft = x = 0.74ft
But remember that the actual width of the image will be two times that, so the width is:
W = 2*0.74ft = 1.48ft
