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barxatty [35]
3 years ago
10

What is the altitude of the triangle?

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0
Area = 1/2 Base x Height

Let x= Base, then x+3 = height

35 = 1/2(x)(x+3)

35 = 1/2(x2) + 3/2(x)

70 = x2 + 3x

x2 + 3x - 70 =0

(x+10)(x-7) = 0, x= -10 or 7 (-1 is impossible) so base = 7, height = 10
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exercise alone. Two methods of collecting data have been proposed. Method I: Recruit volunteers who are willing to participate.
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I) If method I is used, population of generalization will include all those people who may have varying exercising habits or routines.  They may or may not have a regular excersing habit.  In his case sample is taken from a more diverse population

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4 years ago
Solve the following equations for x,
stellarik [79]

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3 csc²(<em>x</em>) = 4

csc²(<em>x</em>) = 4/3

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sin(<em>x</em>) = ± √3/2

<em>x</em> = arcsin(√3/2) + 2<em>nπ</em>  <u>or</u>   <em>x</em> = arcsin(-√3/2) + 2<em>nπ</em>

<em>x</em> = <em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   <em>x</em> = -<em>π</em>/3 + 2<em>nπ</em>

where <em>n</em> is any integer. The general result follows from the fact that sin(<em>x</em>) is 2<em>π</em>-periodic.

In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, the first family of solutions gives <em>x</em> = <em>π</em>/3 and <em>x</em> = 4<em>π</em>/3 for <em>n</em> = 0 and <em>n</em> = 1, respectively; the second family gives <em>x</em> = 2<em>π</em>/3 and <em>x</em> = 5<em>π</em>/3 for <em>n</em> = 1 and <em>n</em> = 2.

(ii) 4 cos²(<em>x</em>) + 2 cos(<em>x</em>) - 2 = 0

2 cos²(<em>x</em>) + cos(<em>x</em>) - 1 = 0

(2 cos(<em>x</em>) - 1) (cos(<em>x</em>) + 1) = 0

2 cos(<em>x</em>) - 1 = 0   <u>or</u>   cos(<em>x</em>) + 1 = 0

2 cos(<em>x</em>) = 1   <u>or</u>   cos(<em>x</em>) = -1

cos(<em>x</em>) = 1/2   <u>or</u>   cos(<em>x</em>) = -1

[<em>x</em> = arccos(1/2) + 2<em>nπ</em>   <u>or</u>   <em>x</em> = 2<em>π</em> - arccos(1/2) + 2<em>nπ</em>]   <u>or</u>   <em>x</em> = arccos(-1) + 2<em>nπ</em>

[<em>x</em> = <em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   <em>x</em> = 5<em>π</em>/3 + 2<em>nπ</em>]   <u>or</u>   <em>x</em> = <em>π</em> + 2<em>nπ</em>

For 0 ≤ <em>x</em> ≤ 2<em>π</em>, the solutions are <em>x</em> = <em>π</em>/3, <em>x</em> = 5<em>π</em>/3, and <em>x</em> = <em>π</em>.

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3 years ago
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Answer:

yes

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By pythagoras' theorem,

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since 65^2 + 72^2 = 97^2, the triangle is a right angled triangle

This is a question on Pythagoras theorem. If you wish to venture further into it/understand this topic better, you may want to follow my Instagram account (learntionary), where I post some of my own notes on certain topics and also some tips that may be useful to you :)

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Answer:

Step-by-step explanation:

Wuh

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3 years ago
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