Question

What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)?

Answer 1

Answer:     c on edgenuety or 3/5x + 1/8

Step-by-step explanation:

Answer 2

The sum of  ( $\frac{2}{5}$ x + $\frac{5}{8}$ ) + ( $\frac{1}{5}$ x - $\frac{1}{4}$ ) is  $\frac{3}{5}$ x +  $\frac{3}{8}$

Step-by-step explanation:

To add or subtract 2 fractions, they must have same denominators, if they not do that

• Find the Lowest common multiple of the two denominators (LCM)
• Replace each denominator by it
• Divide The LCM by each denominator and multiply the numerator of each fraction by its quotient

∵ ( $\frac{2}{5}$ x + $\frac{5}{8}$ ) + ( $\frac{1}{5}$ x - $\frac{1}{4}$ )

- Let us start with adding the like terms

∴  ( $\frac{2}{5}$ x + $\frac{5}{8}$ ) + ( $\frac{1}{5}$ x - $\frac{1}{4}$ ) = (

∵ ( $\frac{2}{5}$ x + $\frac{1}{5}$ x ) have same denominators, then we can add them

∴ ( $\frac{2}{5}$ x + $\frac{1}{5}$ x ) = $\frac{3}{5}$ x

∵  ( $\frac{5}{8}$  - $\frac{1}{4}$ ) do not have the same denominators, then we must find

    LCM of 8 and 4

- The LCM of 8 and 4 is 8 because 8 is the first common multiple

   of 8 and 4

∵ LCM of 8 and 4 is 8

- Divide 8 by the denominator 4

∵ 8 ÷ 4 = 2

- Multiply the numerator of the fraction by 2

∴ $\frac{1}{4}=\frac{2}{8}$

∴  ( $\frac{5}{8}$  - $\frac{1}{4}$ ) = ( $\frac{5}{8}$ - $\frac{2}{8}$ ) = $\frac{3}{8}$

∴  ( $\frac{2}{5}$ x + $\frac{5}{8}$ ) + ( $\frac{1}{5}$ x - $\frac{1}{4}$ ) = $\frac{3}{5}$ x +  $\frac{3}{8}$

The sum of  ( $\frac{2}{5}$ x + $\frac{5}{8}$ ) + ( $\frac{1}{5}$ x - $\frac{1}{4}$ ) is  $\frac{3}{5}$ x +  $\frac{3}{8}$

Learn more:

You can learn more about the fractions in brainly.com/question/2456302

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