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ivolga24 [154]
3 years ago
6

What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)?

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
8 0

Answer:     c on edgenuety or 3/5x + 1/8

Step-by-step explanation:

liubo4ka [24]3 years ago
7 0

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Step-by-step explanation:

To add or subtract 2 fractions, they must have same denominators, if they not do that

  • Find the Lowest common multiple of the two denominators (LCM)
  • Replace each denominator by it
  • Divide The LCM by each denominator and multiply the numerator of each fraction by its quotient

∵ ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} )

- Let us start with adding the like terms

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = (

∵ ( \frac{2}{5} x + \frac{1}{5} x ) have same denominators, then we can add them

∴ ( \frac{2}{5} x + \frac{1}{5} x ) = \frac{3}{5} x

∵  ( \frac{5}{8}  - \frac{1}{4} ) do not have the same denominators, then we must find

    LCM of 8 and 4

- The LCM of 8 and 4 is 8 because 8 is the first common multiple

   of 8 and 4

∵ LCM of 8 and 4 is 8

- Divide 8 by the denominator 4

∵ 8 ÷ 4 = 2

- Multiply the numerator of the fraction by 2

∴ \frac{1}{4}=\frac{2}{8}

∴  ( \frac{5}{8}  - \frac{1}{4} ) = ( \frac{5}{8} - \frac{2}{8} ) = \frac{3}{8}

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = \frac{3}{5} x +  \frac{3}{8}

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Learn more:

You can learn more about the fractions in brainly.com/question/2456302

#LearnwithBrainly

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g100num [7]

Answer:

x = -7

Step-by-step explanation:

2x+3 = x-4

2x-x = -4-3

x = -7

hope it helps ☺️

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Step-by-step explanation:


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Which is equivalent to (2^-3)^4 <br><br> 1/2^12<br><br> 2<br><br> -2^12<br><br> 1/2^7
sleet_krkn [62]

Answer:

The answer is First option

1/2^12 .

\frac{1}{2^{12} }

Step-by-step explanation:

Given:

(2^-3)^4

i.e

(2^{-3} )^{4}

To Find:

(2^{-3} )^{4}=?

Solution:

Law of Indices

(x^{a}) ^{b} =x^{a\times b}\\and\\x^{-1}=\frac{1}{x}

Using the above Property we get

∴ (2^{-3} )^{4}=2^{-3\times 4} \\\\ (2^{-3} )^{4}=2^{-12} \\\\(2^{-3} )^{4}= \frac{1}{2^{12} }

The answer is First option

1/2^12 .

(2^{-3} )^{4}=\frac{1}{2^{12} }

6 0
3 years ago
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